T = 133 + 273 = 406 K
R= 0.0821 L.atm/Kmol
V = 126 L
P= 0.880 atm
n (number of moles) = M/molar mass of KClO3= g/122.54
PV= nRT
PV= M/122.54 RT
M = 407.6 g
You can use the ideal gas law equation PV = nRT to find the moles of oxygen gas produced. Then use the balanced chemical equation for the decomposition of KClO3 to find the mole ratio of KClO3 to O2. Finally, calculate the mass of KClO3 needed using its molar mass.
For every mole of potassium chlorate decomposed, three moles of oxygen are produced. Therefore, 12 moles of potassium chlorate will produce 36 moles of oxygen.
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
The atomicity of KClO3 is one, which means that in one molecule of KClO3, there is one atom each of potassium (K), chlorine (Cl), and oxygen (O).
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.
3 moles of oxygen are obtained from 2 moles of potassium chlorate.M of KClO3 is 122,55 g, M of O2 is 32, density of oxygen is 1,429 g/L.
A 1.80-gram mixture of potassium chlorate, kclo3, and potassium chloride, kcl, was heated until all of the kclo3 had decomposed the liberated oxygen, after drying, occupied 405 ml at 25C when the barometric pressure was 745 torr. This is the problem and the questions were... a. How many moles of O2 were produced? b. What percent of the mixture was KClO3? KCl? Please help!!
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
KClO3
For every mole of potassium chlorate decomposed, three moles of oxygen are produced. Therefore, 12 moles of potassium chlorate will produce 36 moles of oxygen.
kclo3
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
Potassium chlorate (KClO3) has 3 oxygen atoms.
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
O2 is oxygen molecule; KCl is potassium chloride