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% by mass is the mass of the solute divide by the total mass of solution times 100%. Or put another way, % by mass = mass solute/total mass of soln (x100%).Mass solute = 4.35 gMass of solution = 4.35 g + 105 g = 109.35 g (assuming a density of 1g/ml for water)% NaCl by mass = 4.35 g/109.35 g (x100%) = 3.98 % (to 3 significant figures)
Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl
In moles of substance dissolved in 1 L of water -Apex
33% by mass
First of all, you need to know the density of the water. The density can be calculated by 1g/ml. Then the mass of H2O can be calculated by DXV=1x800. Then the total mass of the solution is the mass of solvent plus mass of solute. The percentage is 4.76 for this solution.
9%
number of moles is mass divided by molecular mass. the molecular mass of NaCl is 58.44g/mol. therefore you need 58.44g to make one mole
This concentration of NaCl is 2,6 g NaCl/100 mL solution.
114.14g NaCl
% by mass is the mass of the solute divide by the total mass of solution times 100%. Or put another way, % by mass = mass solute/total mass of soln (x100%).Mass solute = 4.35 gMass of solution = 4.35 g + 105 g = 109.35 g (assuming a density of 1g/ml for water)% NaCl by mass = 4.35 g/109.35 g (x100%) = 3.98 % (to 3 significant figures)
Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl
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Sodium chloride is dissolved and dissociated in water as follow: NaCl-----------------Na+ + Cl-
In moles of substance dissolved in 1 L of water -Apex
Total mass = 4.35 g + 105.0 g = 109.35 g% by mass of NaCl = 4.35/109.35 (x100%) = 3.98% (3 significant figures)
21 pounds
21 Pounds.