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What mass of NaOH is present in a 3.87 L solution with a concentration of 1.53M?
Tanyaspears
Remember the two equations.
moles = mass(g) / Mr &
moles = [conc] X vol(mL)/1000
Combining.
mass(g) / Mr = [conc] x vol(mL) / 1000
Algebraically rearrangeing.
mass(g) = Mr X [ conc ] x vol(mL) / 1000
Mr (NaOH) = 23 + 16 + 1 = 40
conc = 1.53
Vol = 3870 mL
substituting
mass(g) = 40 X 1.53 X 3870 / 1000
mass(g) = 236.844 g ~ 237 g
lenpollock
Wiki User
∙ 12y ago1.53(mol/L) * 39.99(g/mol) * 3.87(L) = 236.8(g) = 237 gram NaOH is present
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How is a solution of NaOH prepared dissolving 20g of NaOH in 500ml of distiled water solved?
The concentration of this solution (in NaOH) is 40 g/L.
Why is it necessary to standardize the NaOH solution before titration?
It allows the concentration of the NaOH to be known.
How do you calculate of NaOH in solution procedure?
The concentration of sodium hydroxide in solution is determined by titration with an acid solution.
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
50 ml of hcl is titrated with a solution of 0.24 m naoh it requires 35 ml of naoh to reach the equivalence point what is the concentration of the hcl solution?
.17
How is a solution of NaOH prepared dissolving 20g of NaOH in 500ml of distiled water solved?
The concentration of this solution (in NaOH) is 40 g/L.
Why is it necessary to standardize the NaOH solution before titration?
It allows the concentration of the NaOH to be known.
What concentration of aqueous NaOH solution freezes at -3.2ºC?
0.86
How do you calculate of NaOH in solution procedure?
The concentration of sodium hydroxide in solution is determined by titration with an acid solution.
A solution is prepared by mixing 360.0 mL of 0.25 M NaOH with 140.0 mL of 0.50 M NaOH and the final concentration is?
The concentration is 12,8 g/L NaOH.
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
What is the concentration of 300.0 mL of an HCl solution that required 16.4 mL of 6.90 M NaOH to neutralize?
The answer would be theoretically , 16.4* 6.9/300=0.3772M But one thing this concentration of NaOH is pretty high, and is not practical to make this solution. Concentration 6.9M means that you'll have to dissolve 40*6.9=286gm NaOH in one 1 litre water. Thus more than 4 gm are present in that 16.4 ml, which is very difficult.
50 ml of hcl is titrated with a solution of 0.24 m naoh it requires 35 ml of naoh to reach the equivalence point what is the concentration of the hcl solution?
.17
What mass of NaOH is in 290 mL of a 1.7 M NaOH solution?
197.2 grams of NaOH is present in 290ml of 1.7 NaoH solution as the formula for Molarity is Mass of solute x 1000/ equivalent mass x volume
What is hypothesis of a acid base titration?
to determine the concentration of the unknown solution and to determine the molar concentration of acetic acid in a sample of vinegar by titrating it with a standard solution of NaOH.
A solution containing 3.76 g naoh in 361 ml water is titrated with 491 ml hcl what is the concentration of hcl in the original solution?
The concentration of hcl is 0.13.
If 55 ml of a 0.211 m NaHO is diluted to a final volume of 125 ml what is the concentration of naoh in the diluted solution?
Are you sure you mean 0.211 m not 0.211 M Is the concentration molality or molarity? If 55 ml of a 0.211 m NaOH is diluted to a final volume of 125 ml what is the concentration of NaOH in the diluted solution?NaOH not NaHO the compound is Sodium hydroxide Molar mass of NaOH = 23 + 16+ 1 = 40 0.211 moles of NaOH = 0.211 * 40 = 8.44 grams of NaOH per liter of solution 55 ml = 0.055 Liter 8.44 grams of NaOH per liter of solution * 0.055 liter = 0.4642 g of NaOH Moles of NaOH = 8.44 ÷ 40 = 0.211 moles 0.211 moles of NaOH in 125 ml = 0.211 moles ÷ 0.125 L = 1.688 m
