The equation for the reaction between sodium and chlorine is 2 Na + Cl2 -> 2 NaCl. This equation shows that equal numbers of formula units of sodium and chlorine are changed during the reaction.
The gram Atomic Mass of two sodium atoms is 2 [exact] X 22.9898 or45.9796. therefore the specified amount of sodium is 92.0/45.9796 or 2.00 double gram atoms, to the justified number of significant digits. Therefore 2.00 double gram atoms of chlorine are required. The gram Atomic Mass of chlorine is 35.453, and four times this amount, or 142 grams of chlorine, to the justified number of significant digits, are needed for complete reaction.
To find the grams of sodium fluoride needed, use the formula: grams = moles x molar mass. First calculate the moles by multiplying the volume (6.3 L) by the molarity (3.6 mol/L). Then multiply the moles by the molar mass of sodium fluoride (41.99 g/mol) to find the grams required. In this case, approximately 920 grams of sodium fluoride are needed.
The density of the marble block is given by the mass divided by the volume. In this case, the density is 920 g / 256 cm3, which equals 3.59 g/cm3.
10 percent of 920 = 92 10% of 920 = 10% * 920 = 10%/100% * 920 = 92
80% of 920 = 80% * 920 = 0.8 * 920 = 736
920
920
920
920
920 = CMXX
920 = CMXX
0.45
All multiples of 920, beginning with these: 920, 1840, 2760, 3680, 4600 . . .