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Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2O

moles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 moles

moles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 moles

mass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)

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6y ago
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12y ago

9.98 * 10^(-3)

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10y ago

hell if i know

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9y ago

The answer is 11,7 g.

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Q: What mass of water is produced from the complete combustion of 2.50x10-3 of methane?
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