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5.8

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The mass of water is 108 g.

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0.916 mol

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20 moles

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Q: How many moles of water form when 5.00L of propane gas completely reacts?
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How much water vapor is produce by propane on combustion?

Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned


How many moles of oxygen will be produced from the complete combustion of 4 moles of propane?

No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.


How many moles of water are produced when ethylene glycol reacts with phtalic anhydride?

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C3H8 plus 5O2---3CO2 plus 4H2O. How many moles of water form when 4.50 L propane gas C3H8 completely react?

5048+w4g5=23vm32


For the reaction 2H2 plus O2 equals 2H2O how much water is produced when 2.5 moles of hydrogen react completely How do you do the problem?

2H2 + O2 ---------------> 2H2O for every 2 moles of hydrogen that reacts, 2 moles of water are produced, thus a 1:1 ratio of water produced to hydrogen reacted. So:- 2.5 moles of hydrogen reacted will produce 2.5 moles of water


When propane undergoes complete combustion in air for each mole of propane burnt how many moles of oxygen are consumed and how many moles of water are formed?

The answer is: 5 moles oxygen and 4 moles H2O.The reaction is:C3H8 + 5 O2 = 3 CO2 + 4 H2O


How many moles of water form when 5.5 moles of oxygen reacts?

Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.


What mass of water forms when 1.45 x g O reacts completely?

1.25xE-3 g/mol O2 reacts completely with 2H2


How many moles of Hydrogen are in 2 moles of H2O?

Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.


What is the number of moles of H2 produced when 23 grams of sodium reacts with water?

The answer is o,5 mol.


what is this answer C3H8 + 5O2 3CO2 + 4H2O?

This answer represents a balanced chemical equation for the combustion of propane (C3H8). When propane reacts with oxygen (O2), it produces carbon dioxide (CO2) and water (H2O).


What is the mass of water produced when 7.01 g of butane reacts in an excess of oxygen?

The equation is 2C4H10 + 13O2 --> 8CO2 + 10H2O This means that for each mole of butane there are 5 moles of water produced. We have 7.01 g of butane = 7.01/58 moles of butane = 0.12 moles. Thus we will get 5 x 0.12 moles of water, = 5 x 0.12 x 18 g of water = 10.88 g.