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The percentage of metal that combines with oxygen can be calculated using the formula: (mass of metal / total mass) * 100%. For example, if 2g of metal combines with 4g of oxygen to form an oxide, the percentage of metal that combines with oxygen is (2g / (2g + 4g)) * 100% = 33.3%.
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How much metal could you extract from 1000 g of an ore containing 1 percent of metal?
From 1000 g of ore containing 1 percent metal, you would be able to extract 10 g of metal. This is calculated by taking 1 percent of 1000 g.
What is the percent by mass of oxygen in MgO?
The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg and 16 g/mol for O). The mass of oxygen in MgO is 16 g, so the percent by mass of oxygen is (16 g / 40.3 g) x 100% ≈ 39.7%.
How find percent compsotion of oxygen in Na2O?
To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.
What is the mass percent of oxygen on SO2?
The molar mass of SO2 is 64.07 g/mol. Oxygen has a molar mass of 16.00 g/mol. To calculate the mass percent of oxygen in SO2, we can divide the molar mass of oxygen (32.00 g) by the molar mass of SO2 (64.07 g) and multiply by 100 to get 50.05%.
What is the percent of oxygen in KClO3?
The percent of oxygen in KClO3 is 48.4%. This can be calculated by dividing the molar mass of oxygen in KClO3 (48 g/mol) by the molar mass of KClO3 (122.55 g/mol) and multiplying by 100%.
What compound is produced when 6.08 g nitrogen combines with 13.92 g oxygen?
When 6.08 g nitrogen combines with 13.92 g oxygen, they will form nitrogen dioxide, which has the chemical formula NO2. This compound is composed of one nitrogen atom and two oxygen atoms.
What is the mass percent A compound contains 14.5 g of magnesium and 3.5 g of oxygen. What is the mass percent of oxygen in the compound?
To find the mass percent of oxygen in the compound, first calculate the total mass of the compound by adding the masses of magnesium and oxygen: 14.5 g + 3.5 g = 18.0 g. Then, use the formula for mass percent: (mass of oxygen / total mass) × 100%. Thus, the mass percent of oxygen is (3.5 g / 18.0 g) × 100% ≈ 19.44%.
How much metal could you extract from 1000 g of an ore containing 1 percent of metal?
From 1000 g of ore containing 1 percent metal, you would be able to extract 10 g of metal. This is calculated by taking 1 percent of 1000 g.
What is the percent composition of the compound that forms when 222.6 g N combines completely with 77.4 g O?
The molar mass of nitrogen (N) is 14 g/mol, and of oxygen (O) is 16 g/mol. Calculate the number of moles of each element. The ratio of the moles of N to O is 3:1. Therefore, the percent composition of the compound is approximately 75% N and 25% O.
What is the percent composition of oxygen in the magnetite Fe3O4?
The molar mass of Fe3O4 is 231.55 g/mol. The molar mass of oxygen is 16.00 g/mol. There are 12 oxygen atoms in Fe3O4, so the total mass of oxygen in Fe3O4 is 192.00 g. Therefore, the percent composition of oxygen in Fe3O4 is (192.00 g / 231.55 g) x 100 = 82.97%.
What is the percent by mass of oxygen in MgO?
The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg and 16 g/mol for O). The mass of oxygen in MgO is 16 g, so the percent by mass of oxygen is (16 g / 40.3 g) x 100% ≈ 39.7%.
How find percent compsotion of oxygen in Na2O?
To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.
What is the mass percent of oxygen on SO2?
The molar mass of SO2 is 64.07 g/mol. Oxygen has a molar mass of 16.00 g/mol. To calculate the mass percent of oxygen in SO2, we can divide the molar mass of oxygen (32.00 g) by the molar mass of SO2 (64.07 g) and multiply by 100 to get 50.05%.
What is the percent of oxygen in KClO3?
The percent of oxygen in KClO3 is 48.4%. This can be calculated by dividing the molar mass of oxygen in KClO3 (48 g/mol) by the molar mass of KClO3 (122.55 g/mol) and multiplying by 100%.
A metal forms two oxidesThe higher oxide contains 80 percent metal 0.72g of lower oxide gave 0.8g of the higher oxide when oxidised Show that the data illustrates the law of multiple proportions?
In higher oxide Metal = 80% Oxygen = (100-80)% = 20% Therefore, we can say that 4 parts of metal combines with 1 part of oxygen. Now, 0.72 g of lower oxide on oxidation gives 0.8 g of higher oxide. It can be assumed that the mass percent of metal in 0.8 g is same as that of 0.72 g of lower oxide. So, Mass of metal in higher oxide = (80/100) x 0.8 g = 0.64 g If in 0.8 g of higher oxide 0.64 g is metal then mass of oxygen present in higher oxide will be (0.8 - 0.64) g = 0.16 g Since, lower oxide contains the same mass of metal as that of higher oxide, we need to calculate the mass of oxygen in lower oxide. Mass of oxygen in lower oxide = (0.72-0.64) g = 0.08 g According to Law to multiple proportions if two elements combine with each other to form two different compounds then the ratio of masses of that element which combines with the other element whose mass is fixed in both the compounds, will be in small whole numbers. Now, in the given problem the mass of metal in both the oxide is fixed so, for the data to illustrate the law of multiple proportion the ratio of mass of oxygen in both the oxides should be in whole numbers. Now, mass of oxygen in higher oxide : mass of oxygen in lower oxide = 0.16 : 0.08 = 2 : 1. Therefore, it can be said that the given data depicts law of multiple proportion.
If 230 g sample of a compound contains 136.6 g of carbon 26.4 g of hydrogen and 31.8 g of nitrogen The rest is oxygen What is the mass percent of oxygen in the compound?
To find the mass percent of oxygen in the compound, first calculate the total mass of the compound by adding the masses of carbon, hydrogen, and nitrogen. The total mass of the compound is 136.6 g (C) + 26.4 g (H) + 31.8 g (N) = 194.8 g. The mass of oxygen can be calculated by subtracting the total mass of the compound from the given mass of the sample: 230 g - 194.8 g = 35.2 g. Therefore, the mass percent of oxygen in the compound is (35.2 g / 230 g) x 100% ≈ 15.3%.
What is the mass percent of oxygen in SO2?
The molar mass of SO2 is 64.07 g/mol. Since oxygen has a molar mass of 16 g/mol and there are 2 oxygen atoms in SO2, the total mass of oxygen in SO2 is 32 g. Therefore, the mass percent of oxygen in SO2 is 32/64.07 * 100% = 50.05%.
