I have no idea what you mean by "most correct product", but assuming that there is sufficient (excess) chlorine, you get lithium chloride and elemental bromine
For A plus 2LiCl + Br2
The products would be Br2 and LiF.
F2 + 2LiBr --> 2LiF + Br2
This is a single displacement reaction.
The products are lithium chloride and bromine.
2LiBr + Cl2 --> 2LiCl + Br2
Chlorine is more reactive than bromine and the displacement is possible.
The chemical equation is:
2 LiBr + Cl2 = 2 LiCl + Br2
THe chemical reaction is:
2 LiBr + Cl2 = 2 LiCl + Br2
2LiCl + Br2
Lithium ion is Li+ and a bromine ion (called a bromide ion) is Br- and the compound formed from them would be LiBr.
Not atoms of LiBr; formula units is correct.1 mol = 6,022 140 857.10e23 (molecules, atoms, ions); this is the Avogadro number.6,022 140 857.10e23 x 1,25 = 7,52767607125.10e23 formula units of LiBr
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
Yes, LiBr is an ionic solid.
LiBr is an ionic compound.
Lithium ion is Li+ and a bromine ion (called a bromide ion) is Br- and the compound formed from them would be LiBr.
The formula for lithium bromide is LiBr. The compound has a molar mass of 86.845 grams per mole. One of its main uses is as a desiccant.
Not atoms of LiBr; formula units is correct.1 mol = 6,022 140 857.10e23 (molecules, atoms, ions); this is the Avogadro number.6,022 140 857.10e23 x 1,25 = 7,52767607125.10e23 formula units of LiBr
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
Yes, LiBr is an ionic solid.
Lithium bromide (LiBr) is a chemical compound.
LiBr is an ionic compound.
LiBr contain 8,139 % lithium and 91,860 % bromine.
LiBr contain 8,139 % lithium and 91,860 % bromine.
Lithium bromide (LiBr) is a compound, not a cation. The cation is Li+.
10 moles LiBr (6.022 X 1023/1 mole LiBr)= 6.022 X 1024 atoms of lithium bromide=========================
LiBr= Lithium bromide==================an ionic compound