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What else can I help you with?
2 r s in the c f?
2 red stripes in the Canadian flag
What is the flag that have letter R at the center?
It was the flag of Rwanda, but Rwanda now has a new flag.
Are there any flag football workouts?
flag football, r u kidding?
What is the meaning of the name Carr?
it is the last name of a person. it is not a car you drive in. that has 1 r this carr has 2 r's just like my last name.
What state has a r in the fourth letter?
There are 2 American states that have "r" as the fourth letter:FloridaGeorgia
What do the colors of Chile flag represent?
th@t w@s mii ? 2! omg! r u single?
What is the national flag with R at the center?
rome
Country whose flag has an r in the center?
Rwanda used such a flag from 1962 through 2001
What country's flag formerly had a large 'R' on it?
The flag that formerly featured a large 'R' belonged to the Republic of the Congo. This flag was used from 1970 to 1991, during a period when the country was known as Zaire under the leadership of Mobutu Sese Seko. The 'R' symbolized "République" and was part of a design that aimed to reflect the country's identity. The flag has since been changed to a new design without the 'R'.
How is Montana different from Florida?
b/c they r 2 different states!
What is the sum of all the positive proper fractions with denominators less than or equal to 100?
Consider a denominator of r; It has proper fractions: 1/r, 2/r, ...., (r-1)/r Their sum is: (1 + 2 + ... + (r-1))/r The numerator of this sum is 1 + 2 + ... + (r-1) Which is an Arithmetic Progression (AP) with r-1 terms, and sum: sum = number_of_term(first + last)/2 = (r-1)(1 + r-1)/2 = (r-1)r/2 So the sum of the proper fractions with a denominator or r is: sum{r} = ((r-1)r/2)/r = ((r-1)r/2r = (r-1)/2 Now consider the sum of the proper fractions with a denominator r+1: sum{r+1} = (((r+1)-1)/2 = ((r-1)+1)/2 = (r-1)/2 + 1/2 = sum{r) + 1/2 So the sums of the proper fractions of the denominators forms an AP with a common difference of 1/2 The first denominator possible is r = 2 with sum (2-1)/2 = ½; The last denominator required is r = 100 with sum (100-1)/2 = 99/2 = 49½; And there are 100 - 2 + 1 = 99 terms to sum So the required sum is: sum = ½ + 1 + 1½ + ... + 49½ = 99(½ + 49½)/2 = 99 × 50/2 = 2475
Is 102 divisible by 4?
No, 102 ÷ 4 = 25 r 2. To check for divisibility by 4, if the last 2 digits are divisible by 4, the whole number is, otherwise the remainder is the same: 102: last 2 digits are '02' = 2 2 ÷ 4 = 0 r 2, so 102 ÷ 4 has remainder 2.
