Cannot be answered without "the following statments" :(
To reference elements in an array, you typically use the array name followed by an index in square brackets. The index usually starts at 0 for the first element, so for an array named arr, the first element would be accessed with arr[0]. For example, arr[1] would reference the second element. Ensure that the index is within the bounds of the array to avoid errors.
An array is a group of related elements, with a common variable name. The index is a number that indicates the position of an element within an array: the 1st. element, the 2nd. element, etc. (many languages start counting at zero).
The value of the kth smallest element in the array is the kth element when the array is sorted in ascending order.
You cannot delete from an array.
which element of the array does this expression reference num[5]
by using index position we can find the particular element in array.
To search, you would start with the first element of the array and compare it with the target value. If the first element matches the target, you found it. If not, you would move to the next element in the array and repeat the process until either you find the target or exhaust all elements in the array.
(array.length - 1) will find the index of the last element in an array (or -1 if the array is empty).
A square array has the same number of columns and rows the array [1] is a square array (a trivial example) the array [1 0] [0 1] is a square array the array [1 0 0 0] [0 1 0 0] [0 0 1 0] [0 0 0 1] is a square array the array [1 0 0 0] [0 1 0 0] [0 0 1 0] is not a square array
The root of the tree is stored in array element [0]; for any node of the tree that is stored in array element [i], its left child is stored in array element [2*i], its right child at [2*i+2]
By returning a pointer to the first element of the array.
Basically, &array[i]; That is, the memory location for an array object with index i. Or, you can do: (array + i);