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In SI units: kJ/kmol
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What is the relation of the molar heat of fusion to the molar heat of vaporization?
Molar heat of fusion: the heat (enthalpy, energy) needed to transform a solid in liquid (expressed in kJ/mol). Molar heat of vaporization: the heat (enthalpy, energy) needed to transform a liquid in gas (expressed in kJ/mol).
When are the quantites molar enthalpies of fusion and molar enthalpy of vaporation used?
Fusion refers to the phase change from liquid to solid (or vv) and vaporization refers to the phase change from liquid to gas (or vv). Heat is either absorbed or released from the substance when these events occur. We use the molar enthalpies to calculat exactly how much heat is transferred during these processes. Ex .. If we are to boil (vaporize) 3 moles of some substance with a known molar enthalpy of vaporization of 120 KJ/mole then we multiply. 3 moles x 120 KJ/mole = 360 KJ of energy is needed for the vaporization to take place.
What is the heat of what energy needed for a substance to change from a liquid state to an gaseous state?
The quantity of heat required to change the temperature of 1g of a substance by 1 celsius is defined as its specific heat or specific heat capacity.Translating the question into "math-speak" will give you the units: it wants to know heat per gram per degree celsius.Heat = J (or cal), per means divide, gram = g, degree celsius = oC, soJ/(g)(oC), which is the unit for specific heat capacity!
What is the energy needed for a substance to change from liquid state to a gaseous state?
thermol
What is the heat of vaporization of alcohol?
Ethanol, which is the alcohol found in alcoholic beverages, has a heat of vaporization 38.6 kJ/mol or 841 kJ/kg.
The molar heats of sublimation and fusion of iodine are 62.3kjmol and 15.3kjmol respectively calculate the molar heat of vaporization of liquid iodide?
It is a known fact : Molar heat of sublimation = molar heat of fusion + molar heat of vaporization so, molar heat of vaporization = molar heat of sublimation - molar heat of fusion Mv = 62.3 kJ/mol - 15.3 kJ/mol Mv = 47 kJ/mol.
What is the relation of the molar heat of fusion to the molar heat of vaporization?
Molar heat of fusion: the heat (enthalpy, energy) needed to transform a solid in liquid (expressed in kJ/mol). Molar heat of vaporization: the heat (enthalpy, energy) needed to transform a liquid in gas (expressed in kJ/mol).
The amount of energy needed to change a material from a solid to a liquid is the heat of what?
The latent heat of evaporation
Estimate the molar heat of vaporization of a liquid whose vapor pressure doubles when the temperature is raised from 85 C to 95 C?
study
The vapor pressure of ethanol is 100 mmHg at 34.9oC and 400 mmHg at 63.5oC What is the molar heat of vaporization of ethanol?
39330 j.mol-1
When are the quantites molar enthalpies of fusion and molar enthalpy of vaporation used?
Fusion refers to the phase change from liquid to solid (or vv) and vaporization refers to the phase change from liquid to gas (or vv). Heat is either absorbed or released from the substance when these events occur. We use the molar enthalpies to calculat exactly how much heat is transferred during these processes. Ex .. If we are to boil (vaporize) 3 moles of some substance with a known molar enthalpy of vaporization of 120 KJ/mole then we multiply. 3 moles x 120 KJ/mole = 360 KJ of energy is needed for the vaporization to take place.
What is the heat of what energy needed for a substance to change from a liquid state to an gaseous state?
The quantity of heat required to change the temperature of 1g of a substance by 1 celsius is defined as its specific heat or specific heat capacity.Translating the question into "math-speak" will give you the units: it wants to know heat per gram per degree celsius.Heat = J (or cal), per means divide, gram = g, degree celsius = oC, soJ/(g)(oC), which is the unit for specific heat capacity!
What is called to the amount of energy needed to melt one mol a substance?
First things first: it's actually spelled "enthalpy", which might be why you're not finding it.If you want a number, you will need to specify a substance.If you just want to know what it means, then in simple terms it's the amount of energy required to evaporate one mole of the substance.
What is the heat of vaporization for gold?
The heat of vaporization for gold is 324 kJ·mol−1.
How many kilojoules of heat are absorbed when 0.38 g of chloroethane (C2H5Cl bp 12.3 and degC) vaporizes at its normal boiling point (The molar heat of vaporization of chloroethane is 26.4 kJmol.)?
The necessary heat is 0,155 kJ.
What is the amount of energy required to change a material from a liquid to a gas?
Latent Heat of Evaporation, or Evaporation Enthalpy. It is given in units of energy over unit of mass, i.e., KJ/Kg.
What is the heat of vaporation of water?
Vaporization heat of water: 40.65 kJ/mol or 2257 kJ/kg or 539.423 calories per gram (very outdated units!)
