It all depends on the load. The formula for calculating amps, volts or ohms (resistance of load) is E=IR, where E is the voltage, I is the current and R is the load or circuit resistance. So, if you know the resistance in ohms and the current in amps, you multiply them together to get the voltage of the circuit. Again, it depends on the load, so a 12 volt car battery can deliver 1.5 amps if the load is 8 ohms whereas a 120 volt circuit will deliver 1.5 amps if the load is 80 ohms. This is all simplified and is based on a resistive load. If the load is capacitive or inductive, then phase angles come into play and the math is more complicated using imaginary numbers and J-operators.
six volts
5.2
6V
When a dc supply is connected to a resistor, current flows. The current in amps is equal to the supply voltage divided by the resistance in ohms. The power used is the voltage times the current, and that appears as heat in the resistor, which might become hot to touch.
No current flows when the the voltage is zero.
Just use Ohm's Law Voltage = Current x Resistance Amps = Voltage Divided By Resistance Amps = 120 / 260
The power dissipated by a 10 ohm resistor with 800v across it is 64 kw.Ohm's law: current is voltage divided by resistancePower law: power is voltage times current, so power is voltage squared divided by resistanceDon't even think about trying this. 64 kw is a lot of power. The resistor will probably explode, or catch fire. At best, the 80 amps required will trip your circuit breaker, if you are lucky.
V = I * R or I = ( V / R ) I = current (amps) V = Voltage R = Resistance The current in a circuit depends on the applied voltage and the resistance of the circuit.
Ohm's law: Volts = amps times ohms In the case of a 4 ohm resistor with 1.5 amps of current, the voltage is 6 volts.
When a dc supply is connected to a resistor, current flows. The current in amps is equal to the supply voltage divided by the resistance in ohms. The power used is the voltage times the current, and that appears as heat in the resistor, which might become hot to touch.
What is the amount of current flowing through the resistor? Voltage drop is dependent on the current. Ohm x Amps = Voltage drop
Too much current flowing in circuit. Sounds like a voltage was applied that exceeded the rating of the resistor. Resistors are rated in watts which is Volts times Amps. As an example, you might have a 1/2 watt rated resistor. If you applied 120 VAC across a 10 Ohm resistance then the current would be 12 Amps. The wattage would be 1,440 watts which is well in access of the rating and would certainly burn out the resistor.
No current flows when the the voltage is zero.
The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
Voltage = Current * ResistanceVoltage = 12VResistance = 10 ohmsCurrent = Voltage/ResistanceCurrent = 12V/10 ohmsCurrent = 1.2 Amps
Just use Ohm's Law Voltage = Current x Resistance Amps = Voltage Divided By Resistance Amps = 120 / 260
The resistor is 1/3 of an ohm. A 9 volt drop across the resistor would cause a draw of 27 amps through the resistor. The wattage you would need for that resistor is at least a 243 watts.
The current is 1.4 amps, as already stated. The voltage is 45 x 1.4 volts.
Like Ohm's Law, the formula for calculating power is a simple product of two quantities. It is given by the formula P = VI, where V is the voltage in volts and I is the current in amperes (or simply amps). So, if you know the value of any two of the quantities, you can easily calculate the third with simple arithmetic. For example, if the current flowing through a resistor is two amps and the voltage drop across that resistor is five volts, the power dissipated by the resistor is, P = VI = 5 volts * 2 amps = 10 watts. If you are given the power and the voltage, you can easily find the current. For example, if you are told that the voltage drop across a resistor is five volts and is dissipating 10 watts, the current through the resistor is 10 watts/5 volts = 2 amps.
V = (I) x (R) = 2 x 12 = 24 volts