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What volume will 1.50 mol of C2H4 gas occupy at STP?
1 mole gas = 22.4L 1.5mol C2H4 x 22.4L/mol = 33.6L ethane gas (C2H4)
What volume will 4.0 mol of helium gas occupy at 300 K and 2.0 ATM?
You can use the ideal gas law to find the volume:PV = nRTV = nRT/P (use R=0.08206 L*atm/mol*K)= (4.0 mol)*(0.08206 L*atm/mol*K)*(300K)/(2.0 atm)V = 49.24 L
What volume will 2.5 mol of hydrogen h2 occupy at -20.0 and 152 kPa?
To find the volume of 2.5 mol of hydrogen gas, we can use the Ideal Gas Law equation: PV = nRT. We are given the pressure (152 kPa), temperature (-20.0 degrees Celsius which is equivalent to 253.15 K), and the number of moles (2.5 mol). We can rearrange the equation to solve for volume (V), V = (nRT)/P. Plugging in the values, V = (2.5 mol x 8.314 J/mol·K x 253.15 K) / 152 kPa = 3.51 L. Therefore, 2.5 mol of hydrogen gas will occupy a volume of 3.51 liters at -20.0 degrees Celsius and 152 kPa.
What does avagadros law say about a gas at STP?
1 mol of any gas has a volume of 22.4 L at STP
What is the volume of 0.05mol of neon gas stp?
The volume of 5.0 moles of 02 at STP is 100 litres.
A chemical reaction produces 0.884 mol of H2S gas What volume will that gas occupy at STP?
The volume is 22,1 L.
What volume will 1.50 mol of C2H4 gas occupy at STP?
1 mole gas = 22.4L 1.5mol C2H4 x 22.4L/mol = 33.6L ethane gas (C2H4)
What volume would 32 g of NO2 gas occupy at 3.12 ATM and 18 Celsius?
(32.0 g/46.0 g/mol) (0.0821 atm) (291.0 K) / 3.12 atm
What volume will 454 grams of H2 occupy at 1.05 atm and 27oC?
125 mol.
What volume will 4.0 mol of helium gas occupy at 300 K and 2.0 ATM?
You can use the ideal gas law to find the volume:PV = nRTV = nRT/P (use R=0.08206 L*atm/mol*K)= (4.0 mol)*(0.08206 L*atm/mol*K)*(300K)/(2.0 atm)V = 49.24 L
What volume will 2.5 mol of hydrogen h2 occupy at -20.0 and 152 kPa?
To find the volume of 2.5 mol of hydrogen gas, we can use the Ideal Gas Law equation: PV = nRT. We are given the pressure (152 kPa), temperature (-20.0 degrees Celsius which is equivalent to 253.15 K), and the number of moles (2.5 mol). We can rearrange the equation to solve for volume (V), V = (nRT)/P. Plugging in the values, V = (2.5 mol x 8.314 J/mol·K x 253.15 K) / 152 kPa = 3.51 L. Therefore, 2.5 mol of hydrogen gas will occupy a volume of 3.51 liters at -20.0 degrees Celsius and 152 kPa.
What is the volume of a 24.7 mol gas sample that has a pressure of 999 ATM at 305 K?
What is the volume of a 24.7 mol gas sample that has a pressure of .999 ATM at 305 K?
What is the volume in liters of 0.75 mol of methane gas (CH4)?
The volume is 17 L.
What is the volume in milliliters of 0.0100 mol of ch4 gas at stp?
One mole has a volume of 22.4l.So the volume is 224ml
What volume will 12.0 mol of 02 occupy at 25k and a pressure of 0.520 ATM?
Using the ideal gas equation: PV=nRT, 0.52atm(V) = 12mol(0.0821)25k. Solve for V to get 47.4 liters.
What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
What is the volume of 0.24 mol oxygen gas at 345 k and a pressure of 0.75 ATM?
The volume is 9,06 L.
