33.3 ml of 3.0 M HCl should be filled up and mixed with water up to 100.0 ml of a 1.0 M HCl solution.
Assuming you want 0.1% weigh/volume, you dissolve 0.1 g mercuric chloride in 100 ml of solution. So, you would weigh out 0.1 g (100 mg) of solid and dissolve in enough solvent to make a final volume of 100 ml.
take the Mr of HCl to be 36.46. to prepare 1.0M we should take 36.46g and dilute to a litre to prepare 0.10M we should take 3.646g and dilute to a litre From density =mass/volume, we get volume=mass/density. So ideally we should take that volume and dilute to a litre. However we know that most conc HCl solution are not 100% HCl. thus we must multiply that volume by a factor 100/x for an HCl solution labelled x% Tauya Chigayo
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
V1M1 = V2M2(x ml)(2 M) = (100 ml)(0.4 M) x = 20 ml Take 20 ml of 2 M magnesium sulfate solution and dilute to a final volume of 100 mls.
39.0g
To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.
Find the volume of the 100% ethanol Add 1/19 of water to the volume (if it is like 190ml, add 10ml of water since 190/200=95%)
It is prepared by taking five volume of ethanol and dissolve in 100 ml of water .
100-120
To prepare a 20% (v/v) solution of ethanol, you need to mix 20 mL of pure ethanol with enough solvent to make a total volume of 100 mL. This means that for every 100 mL of solution, there are 20 mL of ethanol. You can use a volumetric flask to accurately measure the volume of the ethanol and the solvent. It is important to note that the volume of the final solution may not be exactly 100 mL due to the fact that liquid volumes are not necessarily additive.
Assuming you want 0.1% weigh/volume, you dissolve 0.1 g mercuric chloride in 100 ml of solution. So, you would weigh out 0.1 g (100 mg) of solid and dissolve in enough solvent to make a final volume of 100 ml.
take the Mr of HCl to be 36.46. to prepare 1.0M we should take 36.46g and dilute to a litre to prepare 0.10M we should take 3.646g and dilute to a litre From density =mass/volume, we get volume=mass/density. So ideally we should take that volume and dilute to a litre. However we know that most conc HCl solution are not 100% HCl. thus we must multiply that volume by a factor 100/x for an HCl solution labelled x% Tauya Chigayo
volume = mass / volume volume = 100 / 20 volume = 5
If you mean 100 ml of 1 mM CuSO5.H2O, then dissolve 0.1 mmole CuSO4.H2O in sufficient water to make a final volume of 100 ml.molar mass CuSO4.5H2O = 250 g/mole 250 mg = 1 mmole 25 mg = 0.1 mmol Dissolve 25 mg in final volume of 100 mls
The volume of 100 millilitre of hydrochloric acid is:100 mL
The volume is still 100 ml: the shape does not affect the volume.
Measure the volume of 100 drops.Divide by 100.