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What volume of 6.40 m h2so4 is needed to prepare 455.0ml of a solution that is 0.700m in h2so4?
Wiki User
∙ 9y ago
You need 49,8 mL H2SO4 6,4M.
Wiki User
∙ 9y ago
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What volume of 12M HCl solution is needed to prepare 250 mL of 0.100M solution?
25 mL
What final volume would be needed in order to prepare a 0.50 M NaCl solution from 10.0 g of NaCl?
The volume is 342 mL.
What volume of 24 percent citric acid is needed to prepare eight 3 ounce bottles of 10 percent citric acid solution?
300 ml
What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
What volume of 12M HCl solution is needed to prepare 250 mL of 0.100M solution?
25 mL
What final volume would be needed in order to prepare a 0.50 M NaCl solution from 10.0 g of NaCl?
The volume is 342 mL.
Is it possible to prepare 0.1m solution of 0.01M solution?
Yes, by décreasing the volume tenfold.
Prepare a working solution from a stock solution?
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
How many moles of sodium chloride are needed to prepare 500 mL of a 0.250 M solution?
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
What volume of 24 percent citric acid is needed to prepare eight 3 ounce bottles of 10 percent citric acid solution?
300 ml
What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
How do you prepare M Cal solution?
To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.
How do you prepare 6n ammonium hydroxide from 30 percent solution?
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
What is the maximum volume of solution that you can prepare?
Your question does not make sense, an almost infinite amount of solution could be prepared if desired
What volume of a 2.5M stock solution of acetic acid is required to prepare 100.0 milliliters of a 0.50M acetic acid solution?
The answer is 20,15 mL.
