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What volume (in milliliters) of a 0.150 M salt water solution contains 0.500 g of NaCl?
The volume of the solution is 57 mL.
What volume of a 0.150 M salt water solution contains .500g of NaCl?
The volume is 57 mL.
What volume of 2.85M NaCl solution contains .400 mol NaCl?
0,4 mol NaCl is 23,376 g.2,85 mol NaCl is 166,554 g to 1L.140 mL solution NaCl 2,85 M contain 0,4 mol NaCl.
How much 2M Nacl solution would you need to make 250ml of 0.15M Nacl solution?
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
What volume of a 0.150 M saltwater solution contains 0.500 g of NaCl?
Molarity=Moles/Liter.. the answer is .057L or .057mL
The concertration of a water solution of NaCl is 2.48m and it contains 806 g of water How much NaCl is in the solution?
117 grams of NaCl
An example of an isotonic solution?
Normal Saline Solution, or anything that contains 0.9% NaCl
What is the molarity of 750 mL of NaCl solution that contains 21.04 g of NaCl?
The answer is 0,514 mol.
What is the volume of 3.0 M solution of NaCl made with 526g of solute?
Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------
What final volume would be needed in order to prepare a 0.50 M NaCl solution from 10.0 g of NaCl?
The volume is 342 mL.
How would you prepare 30mL of a 5M NaCl solution from a 2M NaCl stock solution?
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
Calculate the number of mL of 1.38 M NaCl solution that contains 147 mg of NaCl?
26328
