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β 14y agoTo answer this question, it is necessary to have an equation for the reaction. The most common such reaction is complete combustion, which follows the equation:
C2H4 + 3 O2 = 2 CO2 + 2 H2O. This equation shows that 3 moles of diatomic oxygen are required to react completely with one mole of C2H4. Therefore, for 1.50 moles of C2H4, 3 X 1.5 = 4.50 moles of oxygen will be required. Oxygen is close to an ideal gas at standard temperature and pressure. Each mole of ideal gas at stp occupies 22.4 liters. Therefore, 4.50 X 22.4 = 101 liters of oxygen, to the justified number of significant digits, will be needed.
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β 14y ago4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
1 mole of gas occupies 22.4 liters at STP. Therefore 3.5/22.4 = 0.15625 moles of SO2. There are thus 0.15625 moles of O2 needed to react with solid sulfur because S + O2 ---->SO2. 0.15625 moles of oxygen occupies 0.15625 x 22.4 liters = 3.5 liters O2 required.
4Na+O2 2Na2O
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
The nunber of moles of oxygen is 2,5.
The answer is 3,375 moles oxygen.
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
The balanced chemical equation for the combustion of pentane C5H12 is: C5H12 + 8O2 β 5CO2 + 6H2O Therefore, for every 1 mole of pentane, 8 moles of oxygen gas are required. So, 0.100 mol of pentane will require 0.100 mol * 8 = 0.800 mol of oxygen gas to react completely.
Assuming complete combustion of butane, you need 15 moles of oxygen to react with 5 moles of butane according to the balanced chemical equation: [ 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O ]
After the reaction is complete, all of the calcium will react with 3.165 mol (since calcium and oxygen react in a 1:1 ratio) of the oxygen gas. This means that there will be 4.00 mol - 3.165 mol = 0.835 mol of oxygen gas left over.
The relative number of moles of hydrogen to moles of oxygen that react to form water represents the stoichiometry of the chemical reaction according to the balanced equation. This relationship reflects the proportions in which the reactants combine to form the products.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
1 mole of gas occupies 22.4 liters at STP. Therefore 3.5/22.4 = 0.15625 moles of SO2. There are thus 0.15625 moles of O2 needed to react with solid sulfur because S + O2 ---->SO2. 0.15625 moles of oxygen occupies 0.15625 x 22.4 liters = 3.5 liters O2 required.
The ratio H/O is 2.
.913 moles
The balanced chemical equation for the reaction between oxygen and C2H2 is: 2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O This means that 5 moles of O2 are required to react completely with 1.0 mole of C2H2.