1.3 ml
(Apex's answer)
3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL
100 mL × × × 40.65 kJ/mol = 226 kJ
1kJ x 1/Hvap x g/mol liquid
The energy required to decompose water into its constituent elements (hydrogen and oxygen) through electrolysis is about 286 kJ per mole of water. Therefore, to decompose 55.5 moles of water would require approximately 15,883 kJ (286 kJ/mole x 55.5 moles).
Melting of 183,3 g ice need 61,14 kJ.
3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL
3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL
This depends on the volume.
This energy is 458,9 kJ/mol.
102 kj
100 mL × × × 40.65 kJ/mol = 226 kJ
For water vapours, 286 kJ/mol.
The enthalpy of vaporization for water is 40,65 kJ/mol.
When 42.5 grams of water freezes, it releases 1784.5 Joules of energy. This energy is given off as the water molecules slow down and form a more ordered solid structure during the freezing process.
1kJ x 1/Hvap x g/mol liquid
1kJ x 1/Hvap x g/mol liquid
kj (kilojoule) is simply a unit to measure energy.