1.3 ml
(Apex's answer)
3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL
100 mL × × × 40.65 kJ/mol = 226 kJ
You have 42.5 g of water. 42.5g H20 / 18.02 g H2O (2.358 moles H2O)*(6.02 Kj/1mole H2O) = 14.1981 Kj =14.2 kJ
1kJ x 1/Hvap x g/mol liquid
When the molar enthalpy of fusion for water is 6.008 kJ/mol, there is 84.4 kJ released when 253 grams of liquid water freezes. 84.4 kJ
3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL
3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL
This depends on the volume.
This energy is 458,9 kJ/mol.
102 kj
100 mL × × × 40.65 kJ/mol = 226 kJ
For water vapours, 286 kJ/mol.
The enthalpy of vaporization for water is 40,65 kJ/mol.
You have 42.5 g of water. 42.5g H20 / 18.02 g H2O (2.358 moles H2O)*(6.02 Kj/1mole H2O) = 14.1981 Kj =14.2 kJ
1kJ x 1/Hvap x g/mol liquid
1kJ x 1/Hvap x g/mol liquid
kj (kilojoule) is simply a unit to measure energy.