You have 42.5 g of water.
42.5g H20 / 18.02 g H2O
(2.358 moles H2O)*(6.02 Kj/1mole H2O)
= 14.1981 Kj
=14.2 kJ
Hfus of water is 333.55 (333.55j/g)(65.8g)=21947.59J 21947.59/1000= 21.947kJ I think
168 kJ
Water boils at 212 oF and freezes at 32 oF; it boils at 100 oC and freezes at 0 oC
Fresh water freezes at a higher temperature than Salt water. So Fresh Water doesn't have to lose as much heat in a given amount of time in order to Freeze.
0
347 J/g.K or 83 cal are released.
Hfus of water is 333.55 (333.55j/g)(65.8g)=21947.59J 21947.59/1000= 21.947kJ I think
Fresh water freezes much much quicker.
167-168 kj
For water vapours, 286 kJ/mol.
6.212
Zero C
The heat of fusion of ethanol is 4.94 kJ/mol-167 - 168 KJ
168 kJ
When water freezes, it turns into what we call ice. ice is a solid. no offense, but um stupid question.
No - water freezes at zero degrees Celsius. The alcohol used in coolants freezes at a much lower temperature.
Water boils at 212 oF and freezes at 32 oF; it boils at 100 oC and freezes at 0 oC