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How does initial concentration of substrate effect enzyme activity?
At low concentration of substrate , rate of enzyme action is directly proportional to conc. of substrate .
If 20.00mL of a 1.50M solution of KBr is diluted to a final volume of 150.0mL what is the new molar concentration?
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
What is the initial pH of the solution in the Erlenmeyer flask?
Q. needs more information on: WHAT is in solution, and at WHAT concentration
What factors the rates of dffusion?
Temperature, initial concentration, and the medium in which diffusion takes place (solid, liquid, or gas).
What is the order of reaction if the half life of a reaction is halved as the initial concentration of the reactant is doubled.?
Second order. If the half life of a reaction is halved as the initial concentration of the reactant is doubled, it means that half life is inversely proportional to initial concentration for this reaction. The only half life equation that fits this is the one for a second-order reaction. t(1/2) = 1/[Ao]k As you can see since k remains constant, if you double [Ao], you will cause t(1/2) to be halved.
What kind of mathematical relationship exists between conductivity and concentration?
The initial concentration affects the conductivity of a solution in a sense that the greater the initial concentration,the greater the conductivity.increase in concentration means presence of more free moving ions in the solution.but this can only occur in the initial concentration because,after the initial concentration,an increase in concentration will mean that there are now more ions present in the solution but the same volume,hence the ions wouldn't be able to move freely an in the initial concentration,hence the conductivity would then decrease since they can't move freely now.
When substrate concentration is equal to km what will be the initial velocity?
Half Km - not sure-
How the absorbance data correlates to the initial protein concentration in ug ml?
The absorbance data correlates to the initial protein concentration in ug ml in one way. It breaks down protein in the stomach by the action of the stomach acid.
How does initial concentration of substrate effect enzyme activity?
At low concentration of substrate , rate of enzyme action is directly proportional to conc. of substrate .
If 20.00mL of a 1.50M solution of KBr is diluted to a final volume of 150.0mL what is the new molar concentration?
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
What does equation V1 c1 v2 c2 stand for where c concentration and v is for volume?
v1= initial volume c1= initial concentration v2= final volume c2= final concentration For example, you have 10mL of an unknown substance with a concentration of 0,5mol/L. If you add 50mL, what will the final concentration be. V1= 10mL C1= 0,5mol/L V2= 60mL C2= x 10/0,5=60/x You must start by putting everything in the same mesure. We'll use mL here. So 0,5-->1000mL= 50-->10mL 50x60= 300 300/10= 30 30 is your C2
Dilute a solution which has an initial concentration of 10 percent down to 2 percent?
Calculating concentration of a chemical solution is a basic skill all students of chemistry must develop early in their studies. What is concentration?
What is the initial pH of the solution in the Erlenmeyer flask?
Q. needs more information on: WHAT is in solution, and at WHAT concentration
Describe the relationship between substrate concentration and the initial reaction rate of an enzyme-catalyzed reaction Is this a linear relationship What happens to the initial reaction rate as sub?
As the substrate concentration increases so does the reaction rate because there is more substrate for the enzyme react with.
How long will it take for the concentration of to decrease to 12.5 percent of its initial concentration when the initial concentration is 0.100?
Find 12.5% of the Molality which is (.1 time .125) which is .0125. The constant in this case is given which is .00692 (k). Multipy the constant times the .0125. so 1/s=.0000865. Now you solve for s. 1/.0000865=s. 10110=s. (This of course is your answer.)
What factors the rates of dffusion?
Temperature, initial concentration, and the medium in which diffusion takes place (solid, liquid, or gas).
How does increasing concentration increases the rate of reaction?
increasing the concentration in a rate of reaction makes the reaction take place faster because if there is more initial particles then there is more particles to react
