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Any chemical reaction between these compounds.

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Q: What will happen if sodium hydrogen carbonate reacts with sodium carbonate?
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What happens when sodium hydrogen carbonate reacts with dilute H2SO4?

2NaHCO3 + H2SO4 --> Na2SO4 + H2O(l) + CO2(g)


Sodium hydrogen carbonate reacts with sodium carbonate plus water plus carbon dioxide?

No, but maybe the question was wrongly interpretable.Better answering, according to this one:Q.:Sodium hydrogen carbonate reacts TO FORM sodium carbonate plus water plus carbon dioxide?A.:Yes, this will happen on (dry) heating or also in solution at higher temperatures!2 NaHCO3 --> Na2CO3 + H2O + (CO2)gas


What is the word equation for the reaction of sulphuric acid and sodium hydrogen carbonate?

Sulphuric acid reacts with sodium hydrogen carbonate to produce sodium sulfate, carbon dioxide, and water.


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Sodium carbonate would be deposited at the bottom of the solution.


What is sodium reactive with?

sodium is white and metallic it is a metal that is essential for life. sodium carbonate reacts with sodium hydrogen sulfate to create a rapid reaction. sodium also reacts with aluminium hydroxide


When vinegar reacts with sodium bi carbonate what happen?

The sodium bicarbonate gives off carbon dioxide (CO2)


What are the product when NaCHO3 reacts with HCl?

Sodium bicarbonate (sometimes called sodium hydrogen carbonate) NsHCO3 reacts with acid to form CO2 NaHCO3 + HCLl = NaCl + H2O +CO2


When hydrochloric acid reacts with sodium hydrogen carbonate why is there fizzing and bubbling?

Because the gas carbon dioxide is produced.


Why is sodium hydrogen carbonate in baking powder?

Sodium hydrogen carbonate is baking powder.


What is the gas given off when dilute hydrochloric acid reacts with sodium carbonate?

The hydrogen chloride: HCl.


What happens when sodium hydrogen carbonate reacts with ethanoic acid?

You will get sodium ethanoate, carbon dioxide and water NaHCO3 + CH3COOH -> CH3COONa + CO2 + H2O


What is the state of hydrogen carbonate?

Sodium hydrogen carbonate is a solid.