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What will happen when excitation system is removed in the on load condition of synchronous generator?
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Why terminal voltage of the self-excited shunt generator lower than that of the separately excited shunt generato?
Some generators are self excited; this means their terminal voltage is fed back to the excitation system to supply power to the rotor of the generator (which makes it into an electromagnet); the more power that is fed back, the stronger the electromagnet becomes, which makes it harder to turn the generator, which causes the generator to push out more power (simplified, really quick version). If there is a fault electrically near the terminal of a self excited generator, the terminal voltage will sage to near zero; this means the voltage supplied to the excitation system will drop by the same percentage (say the terminal voltage is 30% of what it should be, then the maximum supplied voltage to the excitation system drops to 30% of what it normally is, since P = V*I). Since the input power is less, the output of the generator will decrease (current will decrease). The terminal voltage is determined by the impedance between the generator and the fault such that V = I*Z; As I decreases, V will also continue to fall, causing the terminal voltage to sag even more. A non-self excited generator gets its' excitation power from the grid, specifically from a location that is electrically separated from its' terminal voltage. If the terminal voltage sagged to 30% (same fault location as above example), the excitation system voltage may be impacted slightly (say 2%) so the excitation system power is near maximum (98% for this example). Since the excitation system is much farther removed from the terminal voltage, it is not dependent upon it, thus the terminal voltage will not continue to sag as with a self excited system.
What happens if commutator of DC generator is removed?
If the commutator is removed from your generator, you (if you connect slip rings) get AC supply instead of DC supply. the function of the commutator is to convert AC to DC supply and vice versa.Additional AnswerRemoving the commutator will also prevent you from connecting the output of the generator to its load. Remember, the generator's armature is spinning!
What are the methods of stopping a synchronous motor?
My experience with synchronous motors is in the operation of large rotating mills. In that case, the motors are decoupled from the load by means of an air-clutch, and main power is removed from the rotor and the stator. The motor coasts to a stop. If the motor is operated on a variable speed drive, it could be decelerated to very low speed before removing power.
Why is the rotor winding of a synchronous motor connected to an external resistance during start up?
because at start the motor draws larger quantity of current and this may affected the rotor windings in order to limit current always resistance is connected.
What will happen to power delivered by solar cell do when resistance of he load is increased?
A: Nothing will happen if the load increases or even removed the voltage will go to the open voltage condition no harm.
What is loss of excitation in generators?
A loss of excitation will cause the generator to start drawing more and more reactive power over time. Over the first few seconds, and until about thirty seconds after the LOE (depending on the load on the generator before the loss of excitation occurred), active power will stay relatively constant, but reactive power will continue to be absorbed from the rest of the system, and voltage levels will drop. Eventually, the magnetic field between the stator and rotor degrades too much, pole slipping and loss of synchronism will occur. At this point, catastrophic damage will likely have been done to the generator.
Why terminal voltage of the self-excited shunt generator lower than that of the separately excited shunt generato?
Some generators are self excited; this means their terminal voltage is fed back to the excitation system to supply power to the rotor of the generator (which makes it into an electromagnet); the more power that is fed back, the stronger the electromagnet becomes, which makes it harder to turn the generator, which causes the generator to push out more power (simplified, really quick version). If there is a fault electrically near the terminal of a self excited generator, the terminal voltage will sage to near zero; this means the voltage supplied to the excitation system will drop by the same percentage (say the terminal voltage is 30% of what it should be, then the maximum supplied voltage to the excitation system drops to 30% of what it normally is, since P = V*I). Since the input power is less, the output of the generator will decrease (current will decrease). The terminal voltage is determined by the impedance between the generator and the fault such that V = I*Z; As I decreases, V will also continue to fall, causing the terminal voltage to sag even more. A non-self excited generator gets its' excitation power from the grid, specifically from a location that is electrically separated from its' terminal voltage. If the terminal voltage sagged to 30% (same fault location as above example), the excitation system voltage may be impacted slightly (say 2%) so the excitation system power is near maximum (98% for this example). Since the excitation system is much farther removed from the terminal voltage, it is not dependent upon it, thus the terminal voltage will not continue to sag as with a self excited system.
What happens if commutator of DC generator is removed?
If the commutator is removed from your generator, you (if you connect slip rings) get AC supply instead of DC supply. the function of the commutator is to convert AC to DC supply and vice versa.Additional AnswerRemoving the commutator will also prevent you from connecting the output of the generator to its load. Remember, the generator's armature is spinning!
What is the condition where the moisture has been removed?
The condition is called dehydrated.
What condition wherein moisture has been removed?
dgggdg
How to convert Generator to alternator in 1962 falcon?
After the generator is removed, the alternator will have to be mounted where the pulley lines up with the generator belt perfectly. If the alternator does not have a built in regulator then a regulator will have to be installed. If the falcon is a 6 volt system then the starter and all lighting will have to be changed to 12 volts.
Can you reuse laminate flooring that is removed but still in good condition?
Yes
What are the methods of stopping a synchronous motor?
My experience with synchronous motors is in the operation of large rotating mills. In that case, the motors are decoupled from the load by means of an air-clutch, and main power is removed from the rotor and the stator. The motor coasts to a stop. If the motor is operated on a variable speed drive, it could be decelerated to very low speed before removing power.
What is the load rejection and load pick-up in the power generation?
Load rejection occurs when load is suddenly removed from the generator. The most obvious example of this is the breaker connecting the generator to the power grid opens. This results in a full load rejection. Load pick up means the generator is supplying power to a given load. When a generator comes on line, it will pick up some load that might have been supplied by another generator.
How to removed a dc offset from the output of a frequency generator connected to a test circuit?
Run the test signal through a small isolation transformer.
Where is the drain oil plug on a Coleman powermate 6250 generator?
It is directly below where you put in the oil.....it is a small bolt that simply is removed and the oil drained.
What is the password of aqworlds membership and acs generator v4.1?
Hacking is not allowed and will result in your account being suspended/ disabled and all your badges being removed.
