###### Asked in Word Play, Puns, and OxymoronsWord Games

Word Play, Puns, and Oxymorons

Word Games

# What words have 7 letters the third is n?

## Answer

###### Wiki User

###### February 02, 2009 11:02PM

contain denture mankind pancake tangent control contend conceal connect connote confess confine bonfire carnage candela cannery cantata censure central century concave conceal concede concept condemn conduit denizen density dungeon fanatic fanfare fencing fondant general generic genetic genuine genteel hangout handful sincere sinking sandbag

## Related Questions

###### Asked in Algebra, Crossword Puzzles

### How many words of n distinct letters can be formed from the welcome?

So in general, if we want to know how man words can be formed
from 7 letters, we need to understand that order matters so this is
a permutation problem.
There are 7 choice for the first letter, 6 for the second
letter, 5 for the third etc.
So with no repeating letters there would be 7x6x5x4x3x2x1 words.
BUT we have two e's in welcome. So we need to account for that.
Your question is open to a tiny bit of interpretation. If you
want to know how many words of 6 distinct letters can be made from
welcome ( since there are only 6 distinct letters, e being
repeated), then the answer is 6x5x4x3x2x1. However, if we can use
the e twice and the words are distinct, then we simply account for
two e's by diving our answer by 2!, which of course is just 2. So
that would by 7x6x5x4x3x2x1/2.
If we look at n=say 4, distinct letters, then we have 6 choices
for the first, 5 for the second letter, 4 for the third, and 3 for
the last letter.
I would interpret the problem as let n=6,5,4,3,2 or 1. For each
n, how many words can be formed. Then we have 6x5x4x3x2x1 for n=6
and 6x5x4x3x2 doe n=5 and 6x5x4x3 for n=4 etc.
To make this more concrete, let's take on example of n, say n=4.
We could use
w,e,l,c,o, or m for the first letter. Once we used on of those
letters, the next letter in our four letter words, has any of the 5
remaining letters to pick from, then any of the remaining 4 letters
and lastly any of the 3.