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In fashion
rvltzebauzu 7 blanks
what 7 letter words can you spell using the letters CURHLEDOPYXR
The following 7 letter words can be made:LegionsLingoes
I got 7
There are no 6 letter words that contain the 7 letters igwnaeb. The letters can be used to spell words such as began, begin and binge.
There are no 7-letter English words you can make with those letters, even when repeating the letters.
Some words that can be made from the letters O H T I N T N A U are:aanantaunthahathaunthohothihinthithothunthutIininnintoionitnationnononnotnounnunnutohouttainttantattaunttautthanthinthoutintinttontottoutunituntoyouyouth
Twins
Some words that can be made from the letters NEUEING are:engineennuigeegeniegenuinegingnugunIininningenueneeninenun
Mad Hopping.
So in general, if we want to know how man words can be formed from 7 letters, we need to understand that order matters so this is a permutation problem. There are 7 choice for the first letter, 6 for the second letter, 5 for the third etc. So with no repeating letters there would be 7x6x5x4x3x2x1 words. BUT we have two e's in welcome. So we need to account for that. Your question is open to a tiny bit of interpretation. If you want to know how many words of 6 distinct letters can be made from welcome ( since there are only 6 distinct letters, e being repeated), then the answer is 6x5x4x3x2x1. However, if we can use the e twice and the words are distinct, then we simply account for two e's by diving our answer by 2!, which of course is just 2. So that would by 7x6x5x4x3x2x1/2. If we look at n=say 4, distinct letters, then we have 6 choices for the first, 5 for the second letter, 4 for the third, and 3 for the last letter. I would interpret the problem as let n=6,5,4,3,2 or 1. For each n, how many words can be formed. Then we have 6x5x4x3x2x1 for n=6 and 6x5x4x3x2 doe n=5 and 6x5x4x3 for n=4 etc. To make this more concrete, let's take on example of n, say n=4. We could use w,e,l,c,o, or m for the first letter. Once we used on of those letters, the next letter in our four letter words, has any of the 5 remaining letters to pick from, then any of the remaining 4 letters and lastly any of the 3.