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The acceleration due to gravity is proportional to mass and inversely proportional

to the square of distance. So, the acceleration of gravity on the surface of such

a planet, compared to that on the surface of the Earth, would be

(Agrav on Earth) x (9.3/16) = 5.7 meters (18.7 feet) per second2 (rounded)

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Q: What would be the acceleration due to gravity of a planet that has 9.3 m earth and 4 r earth?
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