In theory the formula V = IR (I is current), 12/55 or approximately 0.2 ohms. But in reality the resistance probably will go to infinity, as that much current would almost certainly blow the filament. I doubt any 12 V bulb could dissipate 12*55 = 660 watts for any extended amount of time. But who knows...
The resistance do obstruct the object. The object always travel slower with air resistance. Air resistance is higher with velocity and the object falling through air would have a limited velocity that it can't go through.
The light would split into a rainbow.
Ohm's law applies: Current = Voltage / Resistance As such if you double the resistance of the light bulb you end up with half as much current.
Well, I am also doing this same question and its all about resistance. Resistance is when the electrons flow around a circuit and they collide with ions. These electrons transfer energy to the ions, which consequently get hot and move more so the resistance increases :) So the thicker the wire is, the less resistance it would have because there are more choices of pathways for the electrons can take without colliding with the ions. Therefore less resistance, more current needed to melt the wire. So the thicker the wire is, the more current is needed to melt it
It happens by the refraction of light.
Volts = Current x Resistance. The voltage is where the potential resides for the amount of current flowing through a resistance. Think about the voltage as a potential source of electrons that then flow through a circuit depending on the Load, or resistance in this example.
If you were to put a bare wire belonging to anything in a glass of water, the electricity flowing through the wire would have no reason to continue to travel through the wire instead of dispersing in the water. The water offers less resistance, so the electricity flows through that instead of the wire. This is known as creating a short circuit, or a short, for short! With no electricity flowing through the bulb, it will turn off.
If more electrons were flowing through a wire, the thing that would be increased would be the current. This is the flow of the carriers of electrical charges.
As an example imagine a 60 W light bulb running off 120 V. The current will be 1/2 A. Now assume that you put a second 60 W bulb in series with the first. Now the resistance of the single 60 W bulb is 240 Ohms. The 1/2 A flowing through the bulb heats up the filament wire and causes an amount of light to be emitted. Resistance in series adds, so the total resistance for two of the bulbs in series is 480 Ohms and by Ohms law V = I x R, the current through each bulb will be 1/4 amp and hence the bulbs will be less bright.
An incandescent light bulb is essentially a wire through which current flows. The wire gets heated up and glows giving off light. According to Ohm's Law Volts = Current x Resistance. In this case resistance is the resistance of the filament. Since in a residence the voltage remains more or less constant, the way more energy would be use is if more current passed through the filament. If the resistance of the filament decreased then the current would increase. Not sure how an aging bulb would have a decreased resistance. If this were somehow possible such that the composition of the filament changes and reduced resistance then the energy required to operate the bulb would increase.
I = E/R
It is a voltage (potential) applied to a load that causes a current to flow through the load. Ohm's Law encapsulates this principal and states Volts = Current x Resistance. In your example, the applied voltage would be 200 volts.
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
If blood starts flowing backwards through a valve, stroke volume and ejection fraction would decrease. The heart's pumping action would be less efficient.
Do you mean why is the voltage in a circuit lower after the light bulb than before it? If so, it's because the light bulb filament has electrical resistance. When an electrical current flows through a resistance, there is a voltage drop across the resistance (Ohm's law).More fundamentally, the light bulb is producing light, which is a form of energy. The voltage drop across the light bulb comes from the fact that electrical energy is being turned into light. If voltage didn't drop, you would be producing energy from nothing. Furthermore, if there were no voltage drop, your circuit would behave the same whether you had no light bulbs, one light bulb, or eighteen million light bulbs - something that clearly can't be the case.
If the two 5 ohm resistors were in series, then the current would be 1.2 amperes. If they were in parallel, then the current would be 4.8 amperes. Ohm's Law: Current = Voltage divided by Resistance RSeries = Summation1toN RN RPARALLEL = 1 / Summation1toN (1 / RN)
That would be the sun. It is a star and provides the light and warmth required to support life and flowing water.