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In theory the formula V = IR (I is current), 12/55 or approximately 0.2 ohms. But in reality the resistance probably will go to infinity, as that much current would almost certainly blow the filament. I doubt any 12 V bulb could dissipate 12*55 = 660 watts for any extended amount of time. But who knows...

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Q: What would be the resistance of a 12 volt light bulb with 55 amps flowing through it?
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