44836.82577 Hz
capacitor, inductor, resistor..
just like it soundsseries resonant has capacitor & inductor in seriesparallel resonant has capacitor & inductor in parallel
At resonance, the L and C impedance cancels out, so the current can be calculated based on the resistance and applied voltage. Imagine increasing frequency of the supply from 0 Hz to very high. At low frequency, the impedance of the inductor is ~0 (defined as Zl = w*L*j), and the impedance of the capacitor is very large (defined as Zc = 1 / (w*C*j)). As you increase the frequency, the impedance of the capacitor will decrease, as the impedance of the inductor increases. At some point (the resonant frequency), these two will be equal, with opposite signs. After crossing the resonant frequency, the inductor impedance will continue growing larger than the capacitor impedance until the total impedance approaches infinite.
nai janta
a transformer or inductor or capacitor does not change frequency frequency is controlled at the generating station with the speed of the motor or turbine the number of phases will not make a difference an inductor or capacitor can shift phase up to 90 degrees you can make 3 phase power from single phase power with inductors capacitors and transformers
capacitor,transistor,resistor,inductor
943H
A capacitor alone doesn't have a frequency. The combinationof a capacitor and an inductor (coil) has.-- Read the value of capacitance printed on the capacitor, or measure it. Call it ' C '.-- Read the value of inductance printed on the coil, or measure it. Call it ' L '.The resonant frequency of the combination of those two components isF = 1 / (2 pi) sqrt(L C)
capacitor, inductor, resistor..
The impedance of a component (inductor or capacitor) will change with frequency - resistor impedances will not. Inductor impedance - j*w*L Capacitor impedance - 1/(j*w*C) L = inductance, C = capacitance, j = i = imaginary number, w = frequency in radians The actual inductance and capacitance does not change with frequency, only the impedance.
When an LC tank is excited at the resonant frequency, the energy across each will be equal (but not necessary equal at a given moment in time). If excited at a frequency other than the resonant frequency, the impedance of the inductor (wjL) and capacitor (1/wjC) will not be equal, therefore energy across each will be different.
A tank circuit is used on a radio transmitter. It is an electronic circuit that is used to tune a specific frequency. The tank is made up of two components, an inductor and a capacitor. The two components are connected in a parallel with each other. This is where the term "tank" comes from. Used in a radio transmitter, it is tuned for maximum RF (radio frequency) output on the frequency the transmitter is tuned to.
for inductor, reactance XL = 2*pi* f *L, if frequency doubles then reactance increase. But for capacitor, reactance Xc = 1/(2*pi*f*C). In this case if frequency doubles the reactance decrease.
When an inductor is suddenly connected in parallel with a charged capacitor, the current through the inductor and the voltage between its ends will oscillate at the frequency of F = 1 / 2 pi sqrt(L x C) . With real-world components, having resistance and connected through wire that has resistance, the amplitude of the oscillation will steadily decrease as energy is lost in the circuit, and the oscillation will eventually become too small to measure, and disappear.
With a series RLC circuit the same current goes through all three components. The reactance of the capacitor and inductor are equal and opposite at the resonant frequency, so they cancel out and the supply voltage appears across the resistor. This means that the current is at its maximum, but that current, flowing through the inductor and the capacitor, produces a voltage across each that is equal to the current times the reactance. The voltage magnification is the 'Q factor', equal to the reactance divided by the resistance.
just like it soundsseries resonant has capacitor & inductor in seriesparallel resonant has capacitor & inductor in parallel
The resonant frequency is set by the L and the C: 900 microhenrys and 0.014 microfarad would resonate at a frequency given by: F = 1/ [2 pi sqrt(LC)] If the components are in 'micros' the answer is in Megahertz. In this case the resonant frequency in MHz is: F = 1/ [2 pi sqrt(900 x 0.014)] or 0.0448 MHz, 44.8 kHz. The reactance of the inductor and the capacitor is 253 ohms, so adding a 1000 ohm resistor in parallel would give a tuned circuit with a Q of 1000 / 253 or 3.9.