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What would happen to the power dissipated in the voltage divider?
Wiki User
∙ 12y ago
'Power dissipation' in a voltage divider describes the rate at which energy is transferred from the resistors to the surrounding atmosphere through heat transfer, due to the work done on the resistors by the current flowing through them. If the work done on the resistors causes their temperature to increase faster than heat transfer takes place (a function of the surface area of the resistors), then they will overheat and, possibly, burn out.
Wiki User
∙ 12y ago
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Determine the power dissipated if the voltage supplied to a circuit is 12V and the current measured is 3A?
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
What are advantages of voltage divider bias over the other types of biasing ci?
You can use more than one type of voltage divider in it. It can sometimes get mixed signals with all the things going on.
How do you calculate power dissipated by an IC?
It is very critical to never exceed the input voltage of an IC to begin with. To calculate the power dissipation ( in watts) VxI (Voltage x Current) will give you power in watts.
How do you calculate the maximum power dissipated in diode?
The power dissipated by a diode is P = Vf x I watts, where Vf is the forward voltage drop on diode (typically 0.5 volts for silicon diode) and I is the current.
How do you get half of the voltage from a DC supply circuit?
By using a voltage divider, that is two resistors of the same value in series across the DC supply. Half of the supply voltage will be at the point where the two resistors is connected. But how much wattage of those resistors is also an issue.
Determine the power dissipated if the voltage supplied to a circuit is 12V and the current measured is 3A?
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
What is voltage divider circuit?
The two resistor voltage divider is used often to supply a voltage different from that of an available battery or power supply. In application the output voltage depends upon the resistance of the load it drives.
What process will double the power dissipated by a resistor?
Increase the voltage across the resistor by 41.4% .
What are advantages of voltage divider bias over the other types of biasing ci?
You can use more than one type of voltage divider in it. It can sometimes get mixed signals with all the things going on.
How do you calculate power dissipated by an IC?
It is very critical to never exceed the input voltage of an IC to begin with. To calculate the power dissipation ( in watts) VxI (Voltage x Current) will give you power in watts.
When a 3 ohm resistor draws a current of 4 A when hooked up to a battery of unknown voltage what is the battery's voltage and what is the power dissipated by the resistor?
Voltage can be calculated using Ohm's Law:Voltage = Current (A) x Resistance (Ω)Voltage = 4A x 3Ω = 12 VoltsTherefore, the battery is a 12 Volts.The power dissipated is Voltage x CurrentPower = 4A x 12V = 48 Watts
How do you calculate the maximum power dissipated in diode?
The power dissipated by a diode is P = Vf x I watts, where Vf is the forward voltage drop on diode (typically 0.5 volts for silicon diode) and I is the current.
An arc welder provides 250 A of current when operating with a voltage of 40 V what is the power dissipated by this welder?
10,000 Watts
What power is dissipated if 800v is applied across a 10 ohm resistor?
The power dissipated by a 10 ohm resistor with 800v across it is 64 kw.Ohm's law: current is voltage divided by resistancePower law: power is voltage times current, so power is voltage squared divided by resistanceDon't even think about trying this. 64 kw is a lot of power. The resistor will probably explode, or catch fire. At best, the 80 amps required will trip your circuit breaker, if you are lucky.
What is the power dissipated by a resistor with a current of 2 amps and a resistance of 1000 ohms?
I = 2A R = 1000Ω Power Dissipated P = I2R = (2A)2(1000Ω) = 4000W Voltage across resistor V = IR = (2A)(1000Ω) = 2000V
Three equal resistors connected in series across a voltage source dissipate a power of 10W what sould be the power desipated if same resistors are connected in parallel?
If the voltage and resistance values remain the same the power dissipated will be 90 W.
How do you get half of the voltage from a DC supply circuit?
By using a voltage divider, that is two resistors of the same value in series across the DC supply. Half of the supply voltage will be at the point where the two resistors is connected. But how much wattage of those resistors is also an issue.
