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The power dissipated in a voltage divider circuit is given by the formula P = V^2/R, where V is the voltage across the resistor and R is the resistance of the resistor. If the resistance in the voltage divider circuit is increased, the power dissipated in the circuit will decrease. This is because as resistance increases, the current flowing through the circuit decreases, leading to less power being dissipated as heat in the resistors.
What else can I help you with?
Determine the power dissipated if the voltage supplied to a circuit is 12V and the current measured is 3A?
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
What are advantages of voltage divider bias over the other types of biasing ci?
You can use more than one type of voltage divider in it. It can sometimes get mixed signals with all the things going on.
How do you calculate power dissipated by an IC?
It is very critical to never exceed the input voltage of an IC to begin with. To calculate the power dissipation ( in watts) VxI (Voltage x Current) will give you power in watts.
How do you calculate the maximum power dissipated in diode?
The power dissipated by a diode is P = Vf x I watts, where Vf is the forward voltage drop on diode (typically 0.5 volts for silicon diode) and I is the current.
How do you get half of the voltage from a DC supply circuit?
By using a voltage divider, that is two resistors of the same value in series across the DC supply. Half of the supply voltage will be at the point where the two resistors is connected. But how much wattage of those resistors is also an issue.
What is voltage divider circuit?
The two resistor voltage divider is used often to supply a voltage different from that of an available battery or power supply. In application the output voltage depends upon the resistance of the load it drives.
Determine the power dissipated if the voltage supplied to a circuit is 12V and the current measured is 3A?
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
What are advantages of voltage divider bias over the other types of biasing ci?
You can use more than one type of voltage divider in it. It can sometimes get mixed signals with all the things going on.
What is the power dissipated by a 1.2 Kilohm resistor if the voltage drop across the resistor is W volts?
The power dissipated by a resistor can be calculated using the formula ( P = \frac{V^2}{R} ), where ( P ) is the power, ( V ) is the voltage drop across the resistor, and ( R ) is the resistance. For a 1.2 kilohm resistor (or 1200 ohms), the power dissipated would be ( P = \frac{W^2}{1200} ) watts. Thus, the power dissipated depends on the square of the voltage drop across the resistor divided by 1200.
What process will double the power dissipated by a resistor?
Increase the voltage across the resistor by 41.4% .
If the voltage dropped across a resistor increases by a factor of 10 the power dissipated by the resistor is?
The power dissipated by a resistor is given by the formula ( P = \frac{V^2}{R} ), where ( V ) is the voltage across the resistor and ( R ) is its resistance. If the voltage increases by a factor of 10, the new power can be expressed as ( P' = \frac{(10V)^2}{R} = \frac{100V^2}{R} = 100P ). Therefore, the power dissipated by the resistor increases by a factor of 100.
When a 3 ohm resistor draws a current of 4 A when hooked up to a battery of unknown voltage what is the battery's voltage and what is the power dissipated by the resistor?
Voltage can be calculated using Ohm's Law:Voltage = Current (A) x Resistance (Ω)Voltage = 4A x 3Ω = 12 VoltsTherefore, the battery is a 12 Volts.The power dissipated is Voltage x CurrentPower = 4A x 12V = 48 Watts
How do you calculate power dissipated by an IC?
It is very critical to never exceed the input voltage of an IC to begin with. To calculate the power dissipation ( in watts) VxI (Voltage x Current) will give you power in watts.
How do you calculate the maximum power dissipated in diode?
The power dissipated by a diode is P = Vf x I watts, where Vf is the forward voltage drop on diode (typically 0.5 volts for silicon diode) and I is the current.
An arc welder provides 250 A of current when operating with a voltage of 40 V what is the power dissipated by this welder?
10,000 Watts
How do you get half of the voltage from a DC supply circuit?
By using a voltage divider, that is two resistors of the same value in series across the DC supply. Half of the supply voltage will be at the point where the two resistors is connected. But how much wattage of those resistors is also an issue.
If two resistors of equal value are connected in parallel with each other. The power dissipated by the two resistors will be equal to the sum of the power dissipated by each resistor true or false?
True. When two resistors of equal value are connected in parallel, the total power dissipated by the circuit is indeed the sum of the power dissipated by each resistor. Since they have the same resistance and are subjected to the same voltage, each resistor will dissipate the same amount of power, and their combined power will equal twice that of one resistor.
