Oxygen-17 is stable and does not decay.
Radon-198 does not decay via beta decay. It is thought to decay by alpha decay, but that is not certain. The equation would be ... 86198Rn -> (Alpha, T1/2 = 86 ms) -> 84194Po + 24He2+
Atomic number of radium is 88 and that of bismuth is 83. So atomic number is to be reduced by 5. But as alpha is emitted atomic number reduces by 2. So a beta decay is needed which would increase the atomic number by 1. So 3 alpha decay and one beta decay would make radium into bismuth
Gamma is not a decay process. It is a consequence of a decay process, but it, in itself, is not a decay process. It is the emission of a photon from the excited state of the nucleus in response to a decay process such as alpha or beta that changes the nucleus and leaves it with excess energy.
Alpha decay of any radionuclide would reduce the atomic number by 2 and reduce the atomic mass number by 4. As such, berkelium would decay by alpha emission to americium. Note that not all isotopes of berkelium decay by alpha emission. In terms of percentages, the most predominate example is ... 97247Bk --> (T1/2 = 1380 years) --> 95243Am + 24He2+
238U --> 234Th + 4He 234Th --> 234Pa + e- 234Pa --> 234U + e- 234U --> 234Np + e-, not possible
alpha decay
Radon-198 does not decay via beta decay. It is thought to decay by alpha decay, but that is not certain. The equation would be ... 86198Rn -> (Alpha, T1/2 = 86 ms) -> 84194Po + 24He2+
229Th-------alpha particle-----------225Ra
Sure it will. "Radioactive" means just that - that the corresponding isotope will decay.
A helium nucleus - more precisely, a helium-4 nucleus - is called an alpha particle. The corresponding decay would be called alpha decay.
Polonium-218-------------alpha---------------Lead-214
My book does not list 250Am, nor the product 246Np. Beta decay would probably be preferred in this case over alpha.250Am --> 246Np + 4He
An alpha and beta emission
alpha particles
For example americium-241 decay to neptunium-237 and americium-243 decay to neptunium-239.
If it was a fusion reaction, two small nuclei would have to combine to produce a single larger nucleus. But this is not the case. It is a decay, where a large nucleus is split into smaller particles. If it was Alpha decay, alpha particles would be produced. Alpha particles are helium nuclei and have the symbol 24Alpha. But this is also not the case. Beta-minus particles are just electrons. In this reaction, an electron is produced. So, it's a beta-minus decay. Beta-plus just produces positrons, the anti-particle of the electron, with a positive charge.
Atomic number of radium is 88 and that of bismuth is 83. So atomic number is to be reduced by 5. But as alpha is emitted atomic number reduces by 2. So a beta decay is needed which would increase the atomic number by 1. So 3 alpha decay and one beta decay would make radium into bismuth