The conversion factor you need for this problem is the atomic mass of germanium.
72.6 gram germanium = 1 mole germanium
Since you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from grams Ge, so this goes in the denominator (on the bottom).
grams Ge1 mole Ge = moles Ge72.6 gram Ge
There is no direct relationship between atoms of germanium and grams of germanium. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms Ge, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of Ge, so this goes in the numerator (on the top) of the last factor.atoms Ge1.00 mole Ge72.6 gram= g Ge6.02E+23 atom Ge1.00 mole GeNote that the units atoms germanium "cancel out" in the first factor and you are left in units of moles. Moles cancel out in the second factor and the final units are grams germanium.
The conversion factor you need for this problem is Avogadro's number.(6.02 x 1023 atoms germanium/1 mole germanium) = 1... OR ...(1 mole germanium/6.02 x 1023 atoms germanium) = 1Since you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from atoms Ge, so this goes in the denominator (on the bottom).atoms Ge1 mole Ge = moles Ge6.02E+23 atoms Ge
For this you need the atomic mass of Al. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.54.0 grams Al / (27.0 grams) = 2.00 moles Al
For this you need the atomic mass of Ca. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. Ca= 40.1 grams.761 moles Ca × (40.1 grams) = 30.5 grams Ca
For this you need the atomic (molecular) mass of CH3C6H5. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CH3C6H5=92.1 grams7.51 grams CH3C6H5 / (92.1 grams)= .0815 moles CH3C6H5
The conversion factor you need for this problem is the atomic mass of germanium.72.6 gram germanium = 1 mole germaniumSince you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from grams Ge, so this goes in the denominator (on the bottom).grams Ge1 mole Ge = moles Ge72.6 gram Ge
There is no direct relationship between atoms of germanium and grams of germanium. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms Ge, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of Ge, so this goes in the numerator (on the top) of the last factor.atoms Ge1.00 mole Ge72.6 gram= g Ge6.02E+23 atom Ge1.00 mole GeNote that the units atoms germanium "cancel out" in the first factor and you are left in units of moles. Moles cancel out in the second factor and the final units are grams germanium.
The conversion factor you need for this problem is Avogadro's number.(6.02 x 1023 atoms germanium/1 mole germanium) = 1... OR ...(1 mole germanium/6.02 x 1023 atoms germanium) = 1Since you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from atoms Ge, so this goes in the denominator (on the bottom).atoms Ge1 mole Ge = moles Ge6.02E+23 atoms Ge
For this you need the atomic mass of Al. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.54.0 grams Al / (27.0 grams) = 2.00 moles Al
For this you need the atomic mass of He. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.5.40 moles He × (4.00 grams) = 21.6 grams He
For this you need the atomic mass of Ca. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. Ca= 40.1 grams.761 moles Ca × (40.1 grams) = 30.5 grams Ca
For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaCl=58.5 grams38.0 grams NaCl / (58.5 grams) = .650 moles NaCl
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
For this you need the atomic (molecular) mass of N2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel..713 moles × (69.7 grams) = 49.7 grams Ga
For this you need the atomic mass of He. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.75.0 grams He / (4.00 grams) = 18.8 moles He
For this you need the atomic mass of Pt. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.3.08 moles Pt × (195.1 grams) = 601 grams Pt
For this you need the atomic (molecular) mass of FeCl3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. FeCl3=162.4 grams .200 moles FeCl3