For this you need the Atomic Mass of Al. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.
54.0 grams Al / (27.0 grams) = 2.00 moles Al
To find the volume of 54 grams of aluminum with a density of 2.7 g/cm3, divide the mass by the density: 54 grams / 2.7 g/cm3 = 20 cm3. Therefore, the volume of 54 grams of aluminum is 20 cubic centimeters.
There are 1000 milligrams in a gram. Therefore 54000 milligrams is 54 grams.
To find the mass of the product, first determine the limiting reactant by converting each reactant to moles. Then, use the balanced chemical equation to calculate the theoretical yield of the product. Finally, convert the moles of the product to grams using its molar mass.
There are approximately 11 teaspoons in 54 grams, as 1 teaspoon is roughly equivalent to 4.93 grams.
Remember the Moles Eq'n. moles = mass(g) / Mr The Mr ( Relative molecular mass of Al2O3) is . 2 x Al = 2 x 27 = 54 3 x O = 3 x 16 = 48 54 + 48 = 102 substituting moles(Al2O3) = 6.8 g / 102 moles = 0.0666.... ( recurs to infinity.
To find the volume of 54 grams of aluminum with a density of 2.7 g/cm3, divide the mass by the density: 54 grams / 2.7 g/cm3 = 20 cm3. Therefore, the volume of 54 grams of aluminum is 20 cubic centimeters.
266,86 g aluminium chloride are obtained.
Al2S3
The answer is 3 moles.
54 grams = 0.119049622 pounds
Remember K H D | d c m. Kilograms is three places to the left of grams. So you have to move the decimal place three times to the left. So in this case the answer is 0.054 kilograms.
First take the weight in pounds and multiply it by 453.59. The resulting number is the weight in grams. In this case the answer is 24494.35 grams.
There are 1000 milligrams in a gram. Therefore 54000 milligrams is 54 grams.
54 grams = 0,119 049 6 pound
3.0 moles of H2O have 54 g.
To find this answer it is necessary to first find the chemical formula of aluminum sulfate utilizing the valence charges from the periodic table. Aluminum Sulfate is a molecular formed by the ionic bonding of aluminum to to the polyatomic ion of sulfate Al = +3 SO4 is a polyatomic ion with a charge of -2 Therefore after balancing the equation, you get the chemical formula Al2(SO4)3 Next, in order to find osmolarity, you must first find molarity. This is done by converting grams to moles. Moles are calculated in grams/Liter and is equal to the molecular weight. What is the molecular weight of aluminum sulfate. Looking at the periodic table, you sum the atomic weights of each element, shown in AMUs. Al = 27 (x2) = 54 S = 32 (x3) =96 O = 16 (x12) = 192 We add these up to determine the molecular weight of the substance, which can be used to determine the molarity of this solution. MW = 342g, which means that one mole of aluminum sulfate is 342 grams per liter of water. We can now use the information presented in the above problem to determine molarity 10 grams dissolved in 200 ml of water. Since measurements are in grams per liter, we can assume that if 10 grams were dissolved in 200 ml of water, then 50 grams will dissolve in 1000 ml, or 50 grams per liter (multiply both factors by five). We must use our grams of solute to convert grams into our molarity 50 g x 1 mole/342 grams of aluminum sulfate to determine the molarity. = .15 M At this point, to determine osmolarity, you must be aware that osmolarity is the measure of PARTICLES within a solution per liter. Realizing that aluminum sulfate is held together by an ionic bond, it will freely dissolve in water and produce Al ions and SO4 ions. So we sum the particles of each: 2 Al ions per molecule 3 SO4 ions per molecule Therefore, multiplying the molarity of the aluminum sulfate solution times 5 (total 5 particles from each molecule) will give you the osmolarity. = 0.73 Osm per liter of aqueous solution.
There are approximately 11 teaspoons in 54 grams, as 1 teaspoon is roughly equivalent to 4.93 grams.