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The speed/force which was imparted to it when it left the thrower's hand.
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
A ball is thrown vertically upward with an initial speed of 20m/s. Two second later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24m/s. At what height above the release point will the ball and stone pass each other?
The height of a projectile in motion is dependent on a few different things. The height of a projectile in motion is dependent on weight for example. The height of a projectile in motion will depend on: 1. the gravitational forces acting on it 2. initial height 3. Initial upward (or downward) velocity 4. upward or downward drag forces exerted by the medium it is traveling through (usually air - although it could be a liquid). 5. any upward or downward forces exerted by the independent motion of the medium it is traveling through - updrafts or downdrafts of wind for example.
its upward at some specified angle
The speed/force which was imparted to it when it left the thrower's hand.
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
algebra 2 right? i hated that unit man i forgot everything we learned in that class
A ball is thrown vertically upward with an initial speed of 20m/s. Two second later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24m/s. At what height above the release point will the ball and stone pass each other?
The height of a projectile in motion is dependent on a few different things. The height of a projectile in motion is dependent on weight for example. The height of a projectile in motion will depend on: 1. the gravitational forces acting on it 2. initial height 3. Initial upward (or downward) velocity 4. upward or downward drag forces exerted by the medium it is traveling through (usually air - although it could be a liquid). 5. any upward or downward forces exerted by the independent motion of the medium it is traveling through - updrafts or downdrafts of wind for example.
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
its upward at some specified angle
It takes 5 seconds to reach the top of its path.
The maximum height of a thrown ball is dependent on the upward portion of the initial velocity. Air friction will slow it somewhat but gravity will cause it to lose most of its upward velocity. The velocity will decrease by 9.8 m/sec for each second of its upward motion, until it reaches zero. At that point, the ball is pulled back toward Earth.
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
anything shot up with that initial velocity. There isn't anything in specific.
That's the formula for the height of an object that was tossed upward at a speed of 40 meters per second, after ' t ' seconds . This object has to be something like a canonball, or a baseball pitched by a professional etc. The initial vertical speed of 40 meters per second is almost 90 miles per hour upward !