The speed/force which was imparted to it when it left the thrower's hand.
6.261 m/s
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
mass of the object (times) gravitational acceleration (times) height the object reaches.
The answer for this question cannot be answered as we do not know how much force was applied to the ball for it to reach this height, alough for that height it would be around 3800 newtons
6.261 m/s
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
mass of the object (times) gravitational acceleration (times) height the object reaches.
OW! Not long enough!
The answer for this question cannot be answered as we do not know how much force was applied to the ball for it to reach this height, alough for that height it would be around 3800 newtons
less than the speed it had when thrown upward.
when abody is thrown upward,how many forces act on it?what is the role of the force with which the body has been thrown upward? After a body is thrown upwards, you have gravity pulling it down and friction slowing it.
A ball is thrown vertically upward with an initial speed of 20m/s. Two second later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24m/s. At what height above the release point will the ball and stone pass each other?
There is no such thing as "interconversion of body" in this case. There are energy conversions; perhaps that's what you mean?
velocity is found by dividing the distance with time. In a second the height traveled is found by multiplying the velocity by the time taken and then dividing the answer by two.
ALOT!!