Delta T = imKI = van't Hoff factor = 3 for CaCl2
m = molality = moles solute/kg solvent = ?
K = boiling point constant for water = 0.512
Delta T = change in temperature = 4.4 deg C
Plug in the values and solve for m
I suppose that the molality is 3,73.
The answer is 0,505.
Moles of solute/ kg of solvent = 2 molal solution
== Molality== (1000xMolarity)/((1000xdensity of solution)- (MolarityxMolecular weight of Solute)) ==
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
40%
What is the molality of a solution of 75.2 g AgClO4 dissolved in 885 g C6H6?
The molality is 0,07.
2.5
yes
2mol/kg
The answer is 0,505.
The sodium chloride solution of sodium chloride in water is homogeneous.
This solution contain a specified concentration of sodium chloride.
Sodium chloride is a solid but NaCl can be dissolved in water forming a solution.
-40.1 KJ/mol
When salt is dissolved a water sodium chloride solution is obtained.
2.79