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What is the molality of a solution in which 3.0 moles of NaCl is dissolved in 1.5 Kg of water?
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∙ 12y ago
2mol/kg
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∙ 12y ago
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What is the molality of a solution of 90 grams of glucose C6H12OSUB6 dissolved in 800 grams of water?
first determine the number ofmoles dissolved in given solution then .5 moles moles dissolved in 800g. as comparison with 1000g of water, we know 100g of water dissolve only.1 moles of a glucose so we .7moles of glucose dissolve in 800g.
What is the molality of a solution that has 70g of NaCl dissolved in 300g of water?
Molality(m)= moles of solute divided by kilograms(kg) of solvent you need to find the moles of NaCl by using a conversion factor 70g NaCl = 1mol divided by 58.44g NaCl =1.20mol then you need to convert 300g of water which is the solvent to kilograms by moving the decimal over 3 units to the left which makes .300 kg of solvent Molality= 1.20mol divided by .300kg Molality=4.00
What would you need to do to calculate the molality of 0.2 kilogram of NaCl in 3 kilogram of water?
convert the .2 kg of NaCl to moles of NaCl.
Compute the boiling point elevation of a salt water solution that contains 3.40 g of NaCl dissolved in 148 ml of water?
I believe that you have to convert 3.40g to molality and then use that and multiply it by the constant, .512 and that should give you the answer
What is the freezing point of a solution that contains 2.0 mol of CaCl2 in 800.0 g of water Kf for water equals 1.86Cm?
2.0 mol of CaCl2 releases 2.0 mol of Ca+2 ions & 4.0 mol of Cl- ions = 6 moles of ions find molality: 6 moles / 0.800 kg water = 7.5 molal solution dT = kf (molality) dT = 1.86 C (7.5m) dT = 14 Celsius drop in freezing temp the new freezing point is - 14 C
What is the molality of a solution that contains 2 moles of glycerin and dissolved in 1000 g of water?
Moles of solute/ kg of solvent = 2 molal solution
What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?
The molality is 0,07.
What is the molality of a solution of 90 grams of glucose C6H12OSUB6 dissolved in 800 grams of water?
first determine the number ofmoles dissolved in given solution then .5 moles moles dissolved in 800g. as comparison with 1000g of water, we know 100g of water dissolve only.1 moles of a glucose so we .7moles of glucose dissolve in 800g.
What is the molality of a solution made by dissolving 2 moles of NaOH in 10Kg of water?
Molality =moles of solute/kilograms of solvent Moles of solute =2
What is the molality of a solution composed of 38.0 g of cane sugar (C12H 22O11) dissolved in 175 g of water?
molality = moles solute/kg solvent moles solute = 38.0g x 1 mol/342 g = 0.111 moles kg solvent = 175 g x 1kg/1000g = 0.175 kg molality = 0.111 moles/0.175 kg = 0.635 m
What is the molality of a solution made by dissolving two moles of NaOH in 6 kg of water?
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
What is molality of a solution that has 4 mol of KCI in 0.800 kg of water?
4 mol/0.800 kg
What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?
4 mol over 0.800 kg
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution composed of 20.2 g NaCl dissolved in 685 g of water?
The answer is 0,505.
What is the molality of a solution that has 70g of NaCl dissolved in 300g of water?
Molality(m)= moles of solute divided by kilograms(kg) of solvent you need to find the moles of NaCl by using a conversion factor 70g NaCl = 1mol divided by 58.44g NaCl =1.20mol then you need to convert 300g of water which is the solvent to kilograms by moving the decimal over 3 units to the left which makes .300 kg of solvent Molality= 1.20mol divided by .300kg Molality=4.00
What is the molality of a solution made by dissolving 2 moles of NaOH in 6kg of water?
0.33 mol/kg
