If the gas is ideal, or nearly so, it must be at or nearly at standard temperature and pressure.
It occupies 22.4 L
Because you're in STP conditions, you can use molar volume in a proportion. Molar volume is the volume one mole of an ideal gas will take up at STP: 22.4 liters/mole. To set up a proportion, think: if one mole of a gas occupies 22.4 liters, then 4.0 moles of a gas will occupy x liters.1 mole/22.4 L = 4.0 mole/X Lx = 44.8 liters
Molar volume of gas is the volume which one mole of the gas occupies. According to Avogradro's law, ALL GAS HAVE THE SAME VOLUME AT THE SAME PRESSURE AND TEMPERATURE. So one mole of all gases occupies 22.4dm3 at s.t.p (273K 760mmHg) - i.e 22.4dm3 is the molar volume of all gases at s.t.p. (you can convert to other conditions of temperature and pressure using Boyle's, Charles' or General gas equations)
Molar mass of propane = 44 g/mole ... 100 / 44 = 2.727 moles one mole occupies 22.4 L at STP .... 22.4 x 2.727 = 50.91 L
A mole of gas is equal to 6.02 x 1023 gas molecules.
This is the molar volume of an ideal gas at a given temperature and pressure.
1 mole of gas at STP occupies 22.4 liters.
1 mole of gas = 22.7 litre ( at STP) 22.7 Litre of gas = 1 mole 1 litre of gas = 2.27 litre of gas = mole www.examville.com
1 mole of gas at STP occupies 22.4 liters.
1 mole of gas at STP occupies 22.4 liters.
1 mole (or 4 g of He) occupies 22.414 liters. So, 2.3 mole occupies 2.3 x 22.414 liters = 51.5522 liters
Standard molar volume of the substance.
By knowing the no of moles in a gas. Because , in any gas one mole of gas occupies Avagadro number of molecules.
1 mole of gas at STP occupies 22.4 liters.
It occupies 22.4 L
1 mole of gas at STP occupies 22.4 liters.
It occupies 22.4 L