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You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
One mole of NaOH is 40g. So 40g dissolved in 1 litre will give a 1M solution.
The term molar it refers a form to know the concentration of a solution, and it is equivalent to a molar unit in a litre of solvent 1 Molar (1M) = 1 mole (molecular weight from the structure you are interested in) / 1000 mL or 1 L. Milimolar is the thousandth part from a solution 1M
The pH of PBS is 7.4, which makes it slightly basic. 1M HCl solution has the pH of 1. While it's true that adding a base to an acid will change the pH of the acid, unless you use a very dilute sample of HCl and a very large sample of PBS you will need a very sensitive pH meter to see any pH change.
Sodium hydroxide solution will be on the top.
by adding 158.0g in 1 liter water.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
The ph. for this 1M Na2C4H2O4 solution can be found using the kA and the equation pH = pKa + log([base]/[acid]) This salt Na2C4H2O4 is going to increase the concentration of base in the solution.
A 1M solution of sodium carbonate contains 1 gram formula mass of sodium carbonate dissolved in each liter of solution.
Add 60g of Glacial Acetic Acid to a 1 liter volumetric flask. Make up to the mark with deionized water. The result is 1M acetic acid solution.
Boiling and freezing points are colligative properties, meaning they depend on the number of solute particles dissolve in solution. Glucose is a molecular compound so it is one particle dissolved in solution. CaCl2 will dissociate into three particles in solution. There are three times as many particles present in solution when CaCl2 dissolves.
0.056g
1M
6.023 X 1023 particles make up a 1M solution.
1M glucose means that 1 mole of glucose is dissolved in 1kg of water. Since 1M means 1 molal. And molality is equla to no.of moles of solute per kg of water.
Increase the concentration of NaCl evaporating the water.
1mM DPPH (MW 394.32) solution would be 0.39 mg/1mL 1M = 390 mg/1mL