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The internal air would cool down and contract (lessen) the balloon's volume.
The balloon will shrink when it goes outside. How much it shrinks will depend on the temperature difference. As temperature decreases the gas(ses) in the balloon decrease in volume causing the balloon to shrink.
This is the buoyancy force. Archimedes is credited with first formulating this into a mathematical principle: the buoyancy force of an object is equal to the weight of fluid it displaces. In the case of a hot air balloon, the "fluid" is the outside cool air and the balloon is displacing a volume of cool air equal to the volume of the inflated balloon. So you can say the buoyancy force F = V ρ g, where V is the volume of the inflated ballon, ρ is the outside air density, and g is gravity. A balloon can float because it is displacing this cool air with hot air which is less dense. The volume of hot air inside the balloon thus weighs less than the same volume of cold air outside the balloon. For a balloon to be float upwards, the buoyancy force has to be at least equal to the weight of the balloon (the balloon fabric, the gondola, the people, equipment and cargo, and the hot air inside). For example, for a balloon of 100,000 cubic foot volume (typical), with outside air at 20 deg C near sea level, the buoyancy force is about 7500 lbs. This force has to lift the gondola, people, equipment and of course the hot air inside the balloon, all of which have weight. By far the greatest percentage of that total weight is the heated air inside since there is so much of it.
The air molecules would expand, increasing the pressure of the balloon. When anything gets cold, it contracts, and when heated, it expands. Atoms and molecules are always moving - when something is hot, the molecules are moving faster and greater distances. When something is cold, the molecules are still moving, just slowly and at much smaller distances. You won't see much a difference while it's partially inflated, though there would be one. You can see results more drastically by heating a balloon that is near completely inflated. The more air molecules that are in the balloon, the greater the expansion. In other words, the bigger the balloon and more air that's in it, when heated you will see a larger change in the balloon size.
When the temperature drops gases contract, so the balloon would be less inflated. This is the same reason why tire pressure drops when it gets cold outside.
The volume of the balloon decreases
It decreases. The colder air contracts, making the balloon shrink.
When an inflated balloon is exposed to cold air, provided pressure is constant, the volume will decrease. Bring the balloon back to a warmer spot, and the gas gains kinetic energy from the warm air, and the balloon will plump back up.
The internal air would cool down and contract (lessen) the balloon's volume.
It becomes slightly deflated because the air inside it contracts on cooling.
The balloon will shrink when it goes outside. How much it shrinks will depend on the temperature difference. As temperature decreases the gas(ses) in the balloon decrease in volume causing the balloon to shrink.
the volume of the balloon decreases because the tempature decreased
This is the buoyancy force. Archimedes is credited with first formulating this into a mathematical principle: the buoyancy force of an object is equal to the weight of fluid it displaces. In the case of a hot air balloon, the "fluid" is the outside cool air and the balloon is displacing a volume of cool air equal to the volume of the inflated balloon. So you can say the buoyancy force F = V ρ g, where V is the volume of the inflated ballon, ρ is the outside air density, and g is gravity. A balloon can float because it is displacing this cool air with hot air which is less dense. The volume of hot air inside the balloon thus weighs less than the same volume of cold air outside the balloon. For a balloon to be float upwards, the buoyancy force has to be at least equal to the weight of the balloon (the balloon fabric, the gondola, the people, equipment and cargo, and the hot air inside). For example, for a balloon of 100,000 cubic foot volume (typical), with outside air at 20 deg C near sea level, the buoyancy force is about 7500 lbs. This force has to lift the gondola, people, equipment and of course the hot air inside the balloon, all of which have weight. By far the greatest percentage of that total weight is the heated air inside since there is so much of it.
The air molecules would expand, increasing the pressure of the balloon. When anything gets cold, it contracts, and when heated, it expands. Atoms and molecules are always moving - when something is hot, the molecules are moving faster and greater distances. When something is cold, the molecules are still moving, just slowly and at much smaller distances. You won't see much a difference while it's partially inflated, though there would be one. You can see results more drastically by heating a balloon that is near completely inflated. The more air molecules that are in the balloon, the greater the expansion. In other words, the bigger the balloon and more air that's in it, when heated you will see a larger change in the balloon size.
As we know, Charles's Law states that for a fixed amount of gas at a constant pressure, the volume of the gas changes in the same way that the temperature of the gas changes. So, if a balloon is taken outside on a cold winter day, which means in a low temperature, the volume will also decrease due to the lower temperature.
When the temperature drops gases contract, so the balloon would be less inflated. This is the same reason why tire pressure drops when it gets cold outside.
Actually, it should decrease in size. The volume of a gas is directly proportional to the temperature of a gas (measured in Kelvin). Therefore if you inflate a balloon with your warm breath and then cool it down with cold water, the balloon will shrink, not increase in size.See the Related Questions for more information about the effect of temperature on gases.