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If the gate-channel junction of a JFET was not reverse biased the JFET would just act as a forward biased diode across that junction and the gate would cease to have any control over the channel conductance. For the same reason in a MOSFET the substrate-source/channel/drain junction must remain reverse biased. The MOSFET could not act as a MOSFET.
The electrolytic capacitor should be connected in only one direction.
you should specify: - circuit topology, I assume a series connection. - diode allows current flow? It depends how it's connected - diode forward voltage drop value if diode is in forward conduction, you have VR=10V - VDIODE and, thus, I = VR/R=(10-Vdiode)/1200.
A: Nobody can answer that. It depends on the diode, battery on the meter, scale of the meter. It should never read zero or close to zero ohms and reversing the lead it should just be close to open but it may read some hi k ohms. A meter test is just to find shorted diodes and extremely leaking diode.
ammeter
0.7 The voltage across a silicon diode when it is forward biased should be greater than or equal (>=) 0.7volts.
For a transistor to be in active region : Base Emitter junction should be forward biased and Emitter collector junction should be reverse biased.
When the polarity of the battery is such that electrons are allowed to flow through the diode,then the diode is said to be forward-biased. Conversely, when the battery is "backward" and the diode blocks current, then the diode is said to be reverse-biased. A diode may be thought of as like a switch: "closed" when forward-biased and "open" when reverse-biased.
To know if a transistor is PNP or an NPN,the following should be verified:For a PNP transistor, the base-collector junction is forward biased while the base-emitter junction is reversed biased.For an NPN transistor, the base-emitter junction is forward biased while the base -collector junction is reversed biased.
Emitter-Base junction should be forward biased.Collector-Base junction should be reverse biased.
If the gate-channel junction of a JFET was not reverse biased the JFET would just act as a forward biased diode across that junction and the gate would cease to have any control over the channel conductance. For the same reason in a MOSFET the substrate-source/channel/drain junction must remain reverse biased. The MOSFET could not act as a MOSFET.
The nominal forward bias voltage of a silicon diode is 0.7V, depending on current and temperature. If the cathode is 4.5V, the anode should be around 5.2V.
it is not necessary that always positive voltage should act as a forward bias voltage , it is the potential difference between cathode and anode that makes it forward or reverse biased .it the anode(p- doped material) positive with respect to cathode(n- doped material) --> forward biasedit the anode(p- doped material) negative with respect to cathode(n- doped material) --> reverse biasedex.anode - 5v cathode - 3vanode - 1v cathode - -2vboth the examples are forward biased.
I think that question was biased! It almost made me think you were biased! It should be obvious my answer is biased! Sometimes I think that I.Q. test questions are biased!
The news article was biased towards one political party, making it difficult to get a balanced perspective.
Writers should be cautious to avoid biased language in their writing to ensure inclusivity, respect for diverse perspectives, and accuracy in their communication. Biased language can perpetuate stereotypes, marginalize certain groups, and hinder effective communication with a wide audience. By using neutral and inclusive language, writers can foster a more open and understanding environment for their readers.
If you are testing in a ciruict it could be caused by almost anything (e.g. a capacitor). If you are testing the diode by itself then you probably have an open diode. Normally when testing foreward biased the diode should read .6 ohms and when testing reverse biased it should read 1.2k ohms. ...cont. Yeah if you're dead testing the diode with an ohmmeter and its giving you an infinite reading, you have a blown diode.