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When calculating the number of moles of solid Na2SO4 the factor used is?
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∙ 9y ago
The molar mass of anhydrous sodium sulfate is 142,04.
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∙ 8y ago
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What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
How many moles of Na SO4 are in 25.0 of this compound?
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
How many grams are in 3.6 moles of sodium sulfate?
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
How many Na2SO4 molecules are present in 1.125 moles?
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
How do you determine the number of moles in an element?
Multiply the # of grams by the element's atomic weight. Or if dealing with milliliters, multiply the volume by solutions molarity. When calculating a molecule's # of moles, multiply the # of grams by the molecular weight.
How many moles are in Na2SO4?
just one. If you were given a mass of Na2SO4, then you could find the number of moles by dividing the mass by the molar mass(total of the mass of all elements from the mass on the periodic table). But Na2SO4 by itself is just one mole.
What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
How many moles of Na SO4 are in 25.0 of this compound?
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?
Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced
How many grams are in 3.6 moles of sodium sulfate?
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
Why is stoichiometry useful?
Calculating the mass of a product from the number of moles of reactants APEX
How many moles of sodium in 5.25 mole of Na2SO4?
5,25 moles (in anhydrous sodium sulphate)
How many atoms are in 3.2 moles of Na2SO4?
over 9000 :)
How many Na2SO4 molecules are present in 1.125 moles?
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
Why is stoichiometry used for?
Calculating the mass of a product from the number of moles of reactants APEX
How many moles of solute are present in 1.5 liters of 1.33 M of Na2SO4?
The answer is approx. 2 moles (for anhydrous sodium sulfate).
How many moles of atoms are contained in 2.88g na2 so4?
Full formal set up. 2.88 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(6.022 X 1023/1 mole Na2SO4)(1 mole Na2SO4 atoms/6.022 X 1023) = 0.020 moles of sodium sulfate atoms ------------------------------------------------------( you can see the last two steps are superfluous )
