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No Reaction Occurs (:
No Reaction Occurs (:
Silver shine
copper is placed above the silver in the ractivity series which indicates that copper is more reactive than silver . when a copper coin is kept immersed in a solution of siler nitrate ,silver from its solution will deposit on copper coin . copper slowly displaces silver from the silver nitrate solution and the colour of solution changes from colourless to blue due to the formation of copper nitrate . the copper coin will disappear and silver will percipate out .
The answer is: 2Al + 3Pb(NO3)2 = 2Al(NO3)3 + 3Pb.
No Reaction Occurs (:
No Reaction Occurs (:
Silver shine
copper is placed above the silver in the ractivity series which indicates that copper is more reactive than silver . when a copper coin is kept immersed in a solution of siler nitrate ,silver from its solution will deposit on copper coin . copper slowly displaces silver from the silver nitrate solution and the colour of solution changes from colourless to blue due to the formation of copper nitrate . the copper coin will disappear and silver will percipate out .
Cu(s) + AgNO3(aq) => Ag(s) + CuNO3(aq)
The answer is: 2Al + 3Pb(NO3)2 = 2Al(NO3)3 + 3Pb.
Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag Silver breaks its bond with nitrate and Metallic Copper bonds to the nitrate with Silver changing into its metallic state or 0 charge state.
The molecular formula for copper(II) nitrate and aluminum are Cu(NO3)2 and Al. The balanced reaction involves 3-moles of Cu(NO3)2 reacting with 2-moles of Al to yield 2-moles of aluminum nitrate Al(NO3)3 and 3-moles of Cu.
no reaction
The silver piece of zinc dissolves forming zinc ions. Copper(ii) reduce into copper(i) ions. The blue color of the solution decreases.
the solution turns green and the nails develop a brown deposit which is copper. the iron displaces the copper in the copper sulphate solution. This is because iron is more reactive than copper.
The aluminum metal appears to be turning into copper, but it is actually just removing the metallic copper from its compound state. The Aluminum is oxidized and loses e-, becoming Al 3+ and the copper ions are reduced (they accept those e-) to form solid copper precipitate. The aluminum ions and chloride ions remain in the solution. The reaction will only occur in water and occurs because the transfer of electrons from the aluminum to the copper results in a more stable system.