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Although the height of her forearms above the floor doesn't change during a chin-up, let's assume just for
the sake of simplicity that she lifts her entire total 42.0 kg.

The change in potential energy is (M G H) = (42 x 9.8 x 0.25) = 102.9 joules

The rate at which this energy is delivered is (102.9/2) = 51.45 joules/second = 51.45 watts.

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Q: When doing a chin-up a physics students lifts her 42.0kg body a distances of 0.25 meters in 2 seconds.what is the power deliver by the student?
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