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No. At least not by the force that's perpendicular to the motion. When you push a baby stroller (or a car), you do work, but the force of gravity, downward and perpendicular to the motion, doesn't.
If the force is perpendicular (at 90 degrees) to the direction of motion, that force does no work.
False. You will know nothing at all about any force acting perpendicular to the direction of motion.
When the force acts perpendicular to the direction of motion then it makes it to move along curved path When the force is opposite to motion then it could stop it
False a force at any angle to the direction of motion can not perform work. Power is the rate at which a force is applied.
No. At least not by the force that's perpendicular to the motion. When you push a baby stroller (or a car), you do work, but the force of gravity, downward and perpendicular to the motion, doesn't.
If the force is perpendicular (at 90 degrees) to the direction of motion, that force does no work.
False. You will know nothing at all about any force acting perpendicular to the direction of motion.
When the force acts perpendicular to the direction of motion then it makes it to move along curved path When the force is opposite to motion then it could stop it
When the force acts perpendicular to the direction of motion then it makes it to move along curved path When the force is opposite to motion then it could stop it
False a force at any angle to the direction of motion can not perform work. Power is the rate at which a force is applied.
The centripetal force which always acts perpendicular to the motion of the object
False
Perpendicular (90o). Like whirling an object around on a piece of string. The force is along the string, at right angles to the motion.
Work is zero when the force is perpendicular to the direction of motion, as it is, for example, in a circular gravitational orbit.
Because work done is equal to the force times the distance travelled IN THE DIRECTION of the force. Distance travelled in an oblique direction can be decomposed into two components: s*cos(x) in the direction of the force and s*sin(x) in a direction perpendicular to it (where x is the angle between the force and the resultant motion). Motion in a perpendicular direction is NOT work done by the force, which leaves s*cos(x). Multiply by the force (as required) and you have your answer.
The Centripetal Force