Yes. If your purpose is to analyze a job to determine how it should be performed safely, you would not want to observe an inexperienced worker who may not know how to perform the job well or safely. An experienced worker would more likely perform the job well and make perform fewer unsafe acts while doing so.
The most skilled and experienced employees are often selected as supervisors.
select top 1 * from EMPLOYEE where SALARY < (select MAX SALARY FROM EMPLOYEE) ORDER BY SALARY DESC
select, conceal, observe, non payment, exit
To select the best candidate for the task
Select employee, max(salary) From employee Group by employee Order by one DESC The employee with the max salary will be the first one reported. Another way would be to use a analytical rank function.
Find a good, experienced boot fitter you can trust at a reputable shop.
select * from ( select eno, ename, sal, rank() over(order by sal desc) rnk ) where rnk = 3
The SELECT clause is used to retrieve rows and columns from tables. Ex: Select * from employee
create view vw_active_employee as select * from employee where status = 'Active' after creating the view, view can be used as a table to see active employee. e.g. select * from vw_active_employee Basically we save sql as a database object, so that we can use that in future as a virtual table.
Use the Select statement. As in <?php // If you want all of the data $select = mysql_query("SELECT * FROM table_name"); // where table_name is name of your table // If you want selected data $select = mysql_query("SELECT id, username, password FROM table_name"); // If you want a particular data as in salary of employee named John from table employees $select = mysql_query("SELECT salary FROM employee WHERE Name='john'"); // Remember This only selects the data. Now the fetch part while($fetch = mysql_fetch_array($select)) { // replace the column_name with name of the column fields in database echo $fetch['column_name]; echo $fetch['column_name']; } ?>
yes.... example: select *from employee; dml command in sql language
85/500 = 17%