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When resistors are put in series next to each other their overall resistance is?
Rtot=R1+R2, considering R1 in series with R2
What will happen to the other resistor if the number of resistor decreases?
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
Characteristics of resistor in series and parallel connection?
Resistors in series add resistance to an electrical circuit. For instance two 1 ohm resistors in series will have 2 ohms of resistance. Resistors in parallel divide the resistance between them. Thus two 2 ohm resistors in parallel will have 1 ohms total resistance. resistors of different sizes work the same way. a 4 ohm and 2 ohm resistor in series have 6 ohms resistance. While in parallel they will have .75 ohm resistance. resistance formulas: series: Req = r1+r2+r3....+rx parallel: Req = 1/r1 + 1/r2 + 1/r3 ..... +1/rx
What are Resistors wired in series?
Resistors are wired in series when they are connected in a line. The current flows through the resistors one after the other.
Carbon resistors are not available in market of each number of resistance why?
carbon resistors of standard values are manufactured because other values can be obtained by series and parallel combination of standard values. Moreover even standard values do not offer exact Resistance's will have tolerance
Is resistance in a series circuit equal to the largest resistor in the series?
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!
Given 4 resistors each have equivalent resistance of 100 ohms show how these resistors might be combined to produce an equivalent resistance of a 40 ohms b 250 ohms c 100 ohms?
a) Put 2 of the resistors in series to make a 200 ohm resistor. Then put the 100, 100, and 200 ohm resistors in parallel for 40 ohms. b) Put 2 resistors in parallel for 50 ohms. Put the 50, 100, and 100 ohm resistors in series for 250 ohms. c) Put 2 resistors in parallel for 50 ohms. Repeat with other 2 resistors. Put the two 50 ohm resistors in series for 100 ohms. This configuration can withstand 4 times the wattage of each individual resistor.
How can you get 25ohm total resistance from 100 resistors having 1 ohm resistance?
Connect 50 of them in series. This would have 50 ohm as equivalent. Same way have another 50 pieces in series. This again would have 50 ohm as effective value. Now connect these in parallel to each other. Now the effective would become as 25 ohm.
A 22 k and Ohm and 12 k and Ohm resistor are connected in series across a 68 V source how is the voltage divided?
If the resistors are in series the voltage can not be divided, as it has to pass first through one then the other. The amount of current that flows through a set of resistors in series will be the same at all points and the total resistance in the circuit must be equal to the sum of all the individual resistors added together. In other words the 22k and 12k Ohm resistors are the sames as a single 34k Ohm resistor.
What happens to the voltage values of other resistors when a short occurs in one of them?
If a short occurs in a resistor in series with other resistors, the voltage drops across the other resistors will increase. If a short occurs in a resistor in parallel with other resistors, the voltage drops across the other resistors will decrease, to zero.
What is the equivalent resistance when resistors are in a cube?
The equivalent resistance, from corner to corner, of 12 resistors connected in a cube is 5/6 that of a single resistor.Proof:Start from one corner and flow current through to the opposite corner. You have three resistors. Each of those three resistors is connected to two resistors, in a crisscross pattern. Those six resistors are then connected to three resistors which are connected to the other corner. By symmetry, the voltages at the upper junctions are the same, and then same can be said for the lower junction. You can then simplify the circuit by shorting out the upper junctions and (separately) the lower junctions. This means the circuit is equivalent to three resistors in parallel, in series with six resistors in parallel, in series with three resistors in parallel. This is 1/3 R plus 1/6 R plus 1/3 R, or 5/6 R.
How do you calculate the equivalent resistance of a circuit of the shape of a cube and a having a resistor of i kilo ohm in every branch?
Given twelve 1 KOhm resistors, connected in the shape of a cube, in order to determine the net resistance between opposite corners, first draw the cube in two dimensions. (Try this at each step before continuing, so you can understand the lesson as it unfolds.)There are three resistors leaving the initial vertex, and three resistors entering the final vertex. In between those six resistors, are six more resistors, each pair connected together on one end, and to two other resistors on the other end.If every resistor has the same value, then (by symmetry), the voltage on the ends of the first three resistors must be the same. Similarly, the voltage on the ends of the last three resistors must be the same.If two points in a circuit have the same voltage, then (for purposes of analysis) you can consider them to be shorted together. That short does not change the results, as there is no current flowing through that short.With the bottom ends of the first three resistors shorted, and with the top ends of the last three resistors shorted, the circuit degrades into three resistors in parallel, in series with six more resistors in parallel, in series with three more resistors in parallel.Three 1 KOhm resistors in parallel have a net resistance of 333 ohms. Six have a net resistance of 167 ohms. Two 333 ohm resistors and one 167 ohm resistor in series have a net resistance of 833 ohms, or 5/6 of 1 KOhms.Note: This technique does not work if the resistors are not all the same value. In that case, you would need to solve 12 equations in 12 unknowns, looking at the partial currents in each branch.
