The net force on the object is upward, so
the object accelerates upward in the fluid.
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
No.
If the weight of the object is higher than the buoyant force the object SINKS. And the opposite happens if the weight is lower than the buoyant force. If it is equal, the object neither sink nor float, it is neutrally buoyant.
The buoyant force on any object in a fluid ... whether partially or fully submerged ... isequal to the weight of the fluid displaced by the object. That's related to the object'svolume, and has nothing to do with its weight.
On its volume.
The buoyant force on a fully submerged object is equal to the weight of the water displaced. In fact, that's also true of a floating object.
Since the object is submerged, we know that the buoyant force is not sufficient to overcome the weight of the object, otherwise it would be floating rather than being submerged. Therefore, the buoyant force is equal to the weight of the displaced water, not the weight of the object itself.
It is stationary, regardless of where it is.
They are equal.
The weight of the water displaced by the object is subtracted from the actual weight of the object (out of water), leaving the object with a net positive weight while submerged.
No, but the difference between the buoyant force and the weight of the object will determine whether it floats or sinks.
That completely depends on the object's volume (which you have not mentioned). The buoyant force on it is equal to the weight of an equal volume of water.