The second bulb will also turn off since removing one bulb breaks the circuit, disrupting the flow of electricity to both bulbs. The circuit needs to be complete for electricity to flow and illuminate the bulbs.
Yes, a circuit with two light bulbs connected in series can light up. Current flows through the first light bulb, then through the second, allowing both bulbs to illuminate. If one bulb burns out, however, both bulbs will go out.
If you increase the number of bulbs in a circuit, the resistance in the circuit will increase, causing the motor's speed to decrease. If you decrease the number of bulbs, the resistance in the circuit will decrease, causing the motor's speed to increase.
The voltage in a series circuit is divided among the bulbs, so as more bulbs are added in series, each bulb receives less voltage. This causes the brightness of each bulb to decrease compared to when fewer bulbs are present.
When two light bulbs are connected in series, the total voltage of the circuit is divided between the two bulbs, resulting in each bulb receiving less voltage than if they were connected individually. This reduces the brightness of both bulbs compared to when they are connected individually.
the one is not light
As a series circuit, as asked, all bulbs will go off because of that just one bulb.
Twenty .02 Hundredths placewhat
The second bulb will also turn off since removing one bulb breaks the circuit, disrupting the flow of electricity to both bulbs. The circuit needs to be complete for electricity to flow and illuminate the bulbs.
current in series always stays the same
matter
36
The other bulb remain to glow with same intensity.
The filament breaks.
nothing
Two bulbs in parallel are brighter than the same two bulbs in series, given the same potential voltage, because there is twice the available voltage to each bulb.
Of course. The circuit in my house has two door buzzers and almost 30 bulbs.