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friction
Work = force x distance = Newtons x meters = 1937 Joules.
For every action there is an equal and opposite reaction, so if you push on a crate, the crate pushes back with a normal force equal to the force exerted. Thus, expect a force of 50 N to push back at you. However, if you meant the normal force of the ground exerted on the box, then that would included the 50 N force and the weight of the crate.
Force
compressive force
friction
Work = force x distance = Newtons x meters = 1937 Joules.
For every action there is an equal and opposite reaction, so if you push on a crate, the crate pushes back with a normal force equal to the force exerted. Thus, expect a force of 50 N to push back at you. However, if you meant the normal force of the ground exerted on the box, then that would included the 50 N force and the weight of the crate.
The weight of the crate is acting downward on the ground and the ground is exerting a force equal to the weight of the crate upward on the crate.
The weight of the crate is acting downward on the ground and the ground is exerting a force equal to the weight of the crate upward on the crate.
Fnet = F1+F2Force of man f1 = 10nForce of goat f2 = 10nSo,Fnet = 10+10Fnet=20n================================-- If Fred and the man are both pushing in the same direction, thenthe net force is 20 newtons.-- If they're not both pushing in the same direction, then the net forceis less than 20 N, but we don't have enough information to be able tonail down either the net force or its direction.
Force
compressive force
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
Friction force = -F The crate is at rest, so all forces must be balanced
The buoyant force pushes you toward the surface.
We must assume that the force pushes parallel to the floor.Work = (force) x (distance) = (800) x (1.5) = 1,200 newton-meters = 1,200 joules