The Answer To Your Question Is.... tin (IV) oxide
The Roman numeral IV indicates 4 (-1+5 = 4)
Assuming that both elements are in their most common isotopes, Tin IV oxide has 86 neutrons (Tin 70, Oxygen 8 x2)
The formula of lead (II) sulphide is PbS whilst the formula of lead (IV) sulphide is PbS2. The formula is: PbS and the number of Solubility product constants is 3x10^-25 if you're interested;)
Tin (II) hydroxide
The chemical formula for tin (IV) sulfide is SnS2.The chemical formula for tin (II) sulfide is SnS.
Tin (IV) Sulfide It is ionic :)
i think its Sn(SO3)4
SnS2 is the chemical formula of tin(IV) sulfide or tin disulfide.
TiS for titanium sulfide (titanium(II) sulfide) and TiS2 for titanium disulfide (titanium(IV) sulfide)
Lead IV Sulfide is PbS2
*Tin Sulfate* NO! This is WRONG!SnS2 is Tin(IV) Sulfide, not Tin SulfateThe (IV) means that Tin has a 4+ charge (can be Tin(II) with a 2+ charge or Tin(IV))Sulfur has a 2- charge, so it takes 2 Sulfur ions to balance out the chargesso you have 1 Tin Ion with a charge of 4+ and 2 Sulfur Ions with charges of 2+put them together and it makes SnS2Sulfate is a polyatomic ion with the formula SO4 with a 2- charge, so the formula for Tin Sulfate would be Sn(SO4)2
The Answer To Your Question Is.... tin (IV) oxide
Tin (IV) phosphide
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
Sn4+ is the symbol for Tin(IV), that is, the element tin with a oxidation state of 4.
Lead(II) Sulfide = PbS Lead(IV) Sulfide = PbS2